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Velocity of sound waves in air is 330 m/s. For a particular sound in air a path difference of 40 cm is equivalent to phase difference of 1.6π. The frequency of the wave is
- a)165 Hz
- b)150 Hz
- c)660 Hz
- d)330 Hz
Correct answer is option 'C'. Can you explain this answer?
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Most Upvoted Answer
Velocity of sound waves in air is330 m/s.For a particular soundin air ...
Option C 660Hz is correct answer... pi=2×
π×mu/velocity × X 1.6π=2×π×mu/330×0.4. (40 cm convert to m) calculate this u get the answer. So mu i.e,frequency of wave=660 Hz.
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Velocity of sound waves in air is330 m/s.For a particular soundin air ...
Understanding the Problem
To find the frequency of the sound wave, we can use the relationship between path difference, phase difference, and frequency.
Key Information Provided
- Velocity of sound in air (v) = 330 m/s
- Path difference (d) = 40 cm = 0.4 m
- Phase difference (Δϕ) = 1.6π radians
Relationship Between Phase Difference and Path Difference
The relationship between path difference and phase difference is given by the formula:
Δϕ = (2π/λ) * d
Where λ is the wavelength.
Finding Wavelength
From the given phase difference and path difference:
1. Rearranging the formula gives us:
λ = (2π * d) / Δϕ
2. Substituting the values:
λ = (2π * 0.4) / (1.6π)
3. Simplifying this:
λ = 0.4 * (2 / 1.6) = 0.5 m
Calculating Frequency
Now, we can find the frequency (f) using the formula:
f = v / λ
1. Substituting the known values:
f = 330 m/s / 0.5 m
2. This gives us:
f = 660 Hz
Conclusion
Thus, the frequency of the sound wave is:
Correct Answer: c) 660 Hz
To find the frequency of the sound wave, we can use the relationship between path difference, phase difference, and frequency.
Key Information Provided
- Velocity of sound in air (v) = 330 m/s
- Path difference (d) = 40 cm = 0.4 m
- Phase difference (Δϕ) = 1.6π radians
Relationship Between Phase Difference and Path Difference
The relationship between path difference and phase difference is given by the formula:
Δϕ = (2π/λ) * d
Where λ is the wavelength.
Finding Wavelength
From the given phase difference and path difference:
1. Rearranging the formula gives us:
λ = (2π * d) / Δϕ
2. Substituting the values:
λ = (2π * 0.4) / (1.6π)
3. Simplifying this:
λ = 0.4 * (2 / 1.6) = 0.5 m
Calculating Frequency
Now, we can find the frequency (f) using the formula:
f = v / λ
1. Substituting the known values:
f = 330 m/s / 0.5 m
2. This gives us:
f = 660 Hz
Conclusion
Thus, the frequency of the sound wave is:
Correct Answer: c) 660 Hz
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Velocity of sound waves in air is330 m/s.For a particular soundin air a path difference of 40 cm isequivalent to phasedifference of 1.6π. The frequency of the wave isa)165 Hzb)150 Hzc)660 Hzd)330 HzCorrect answer is option 'C'. Can you explain this answer?
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Velocity of sound waves in air is330 m/s.For a particular soundin air a path difference of 40 cm isequivalent to phasedifference of 1.6π. The frequency of the wave isa)165 Hzb)150 Hzc)660 Hzd)330 HzCorrect answer is option 'C'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Velocity of sound waves in air is330 m/s.For a particular soundin air a path difference of 40 cm isequivalent to phasedifference of 1.6π. The frequency of the wave isa)165 Hzb)150 Hzc)660 Hzd)330 HzCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Velocity of sound waves in air is330 m/s.For a particular soundin air a path difference of 40 cm isequivalent to phasedifference of 1.6π. The frequency of the wave isa)165 Hzb)150 Hzc)660 Hzd)330 HzCorrect answer is option 'C'. Can you explain this answer?.
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Velocity of sound waves in air is330 m/s.For a particular soundin air a path difference of 40 cm isequivalent to phasedifference of 1.6π. The frequency of the wave isa)165 Hzb)150 Hzc)660 Hzd)330 HzCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for Velocity of sound waves in air is330 m/s.For a particular soundin air a path difference of 40 cm isequivalent to phasedifference of 1.6π. The frequency of the wave isa)165 Hzb)150 Hzc)660 Hzd)330 HzCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of Velocity of sound waves in air is330 m/s.For a particular soundin air a path difference of 40 cm isequivalent to phasedifference of 1.6π. The frequency of the wave isa)165 Hzb)150 Hzc)660 Hzd)330 HzCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
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