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Cyclic photophosphorylation differs from non-cyclic photophosphorylation because it:
  • a)
    Produces both ATP and NADPH
  • b)
    Only involves Photosystem I
  • c)
    Does not produce oxygen
  • d)
    Requires the presence of carbon dioxide
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
Cyclic photophosphorylation differs from non-cyclic photophosphorylati...
Cyclic photophosphorylation only involves Photosystem I and is characterized by the flow of electrons in a cycle within Photosystem I. It differs from non-cyclic photophosphorylation, which involves both Photosystem I and II, produces oxygen, ATP, and NADPH, and does not directly involve carbon dioxide.
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Cyclic photophosphorylation differs from non-cyclic photophosphorylati...
Non-Cyclic Photophosphorylation vs. Cyclic Photophosphorylation

Non-Cyclic Photophosphorylation:
- Involves both Photosystem I and Photosystem II
- Produces both ATP and NADPH
- Generates oxygen as a byproduct
- Requires the presence of water to provide electrons for Photosystem II

Cyclic Photophosphorylation:
- Only involves Photosystem I
- Produces ATP but not NADPH
- Does not produce oxygen
- Does not require the presence of water
- Electrons cycle back to Photosystem I after being excited, leading to the production of ATP without the formation of NADPH

Explanation:
Cyclic photophosphorylation differs from non-cyclic photophosphorylation mainly because it only involves Photosystem I, unlike non-cyclic photophosphorylation which involves both Photosystem I and Photosystem II. As a result, cyclic photophosphorylation only produces ATP and does not generate NADPH or oxygen. This process is essential for providing ATP for cellular processes in certain organisms, especially in situations where high ATP production is needed without the simultaneous production of NADPH.
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Cyclic photophosphorylation differs from non-cyclic photophosphorylation because it:a)Produces both ATP and NADPHb)Only involves Photosystem Ic)Does not produce oxygend)Requires the presence of carbon dioxideCorrect answer is option 'B'. Can you explain this answer?
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