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There are three numbers in an arithmetic progression. If the two larger numbers are increased by one, then the resulting numbers are prime. The product of these two primes and the smallest of the original numbers is 598. Find the sum of the three numbers.
  • a)
    45
  • b)
    29
  • c)
    42
  • d)
    36
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
There are three numbers in an arithmetic progression. If the two large...
Let three numbers are 2,12,22
Two larger numbers are increased by 1 : 13,23
New three numbers : 2,13,23
Product of these numbers is equal to 598.
=> 2*13*23 = 598
Sum of the three numbers = 2+13+23 
= 36
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Most Upvoted Answer
There are three numbers in an arithmetic progression. If the two large...
I think answer will be 36.Because if you take three no. 2,12,22. If we increase larger numbers by 1 than 2,13,23 We get 2×13×23=598So the sum of no. Must be 2+12+22=36
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Community Answer
There are three numbers in an arithmetic progression. If the two large...
Let three numbers are 2,12,22
Two larger numbers are increased by 1 : 13,23
New three numbers : 2,13,23
Product of these numbers is equal to 598.
=> 2*13*23 = 598
Sum of the three numbers = 2+13+23 
= 36
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