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The average of 5 consecutive even numbers A, B, C, D and E is 52. What is the product of B and E?
- a)2916
- b)2988
- c)3000
- d)2800
- e)None of these
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
The average of 5 consecutive even numbers A, B, C, D and E is 52. What...
Let the five consecutive even numbers be x,
x + 2, x + 4, x + 6 and x + 8 respectively.
According to the question,
x + x + 2 + x + 4 + x + 6 + x + 8 = 5 × 52
B = x + 2 = 48 + 2 = 50 and E = x + 8 = 48 + 8 = 56
B × E = 50 × 56 = 2800
x + 2, x + 4, x + 6 and x + 8 respectively.
According to the question,
x + x + 2 + x + 4 + x + 6 + x + 8 = 5 × 52
B = x + 2 = 48 + 2 = 50 and E = x + 8 = 48 + 8 = 56
B × E = 50 × 56 = 2800
So, the correct option is 'D'
Most Upvoted Answer
The average of 5 consecutive even numbers A, B, C, D and E is 52. What...
Let the five consecutive even numbers be x,
x + 2, x + 4, x + 6 and x + 8 respectively.
According to the question,
x + x + 2 + x + 4 + x + 6 + x + 8 = 5 × 52
B = x + 2 = 48 + 2 = 50 and E = x + 8 = 48 + 8 = 56
B × E = 50 × 56 = 2800
x + 2, x + 4, x + 6 and x + 8 respectively.
According to the question,
x + x + 2 + x + 4 + x + 6 + x + 8 = 5 × 52
B = x + 2 = 48 + 2 = 50 and E = x + 8 = 48 + 8 = 56
B × E = 50 × 56 = 2800
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Community Answer
The average of 5 consecutive even numbers A, B, C, D and E is 52. What...
So the series should be 48 50 52 54 56 so the product of 50*56=2800 You could go by long method let numbers be x x+2 x+4 x+6 x+8 so add them you will get 5x+ 20 /5 =52 so by solving you will get 48 50 52 54 56 so 50*56=2800
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