Two ions of the same charge and energy but different mass are passing ...
**Explanation:**
When charged particles move through a magnetic field, they experience a force known as the magnetic Lorentz force. This force acts perpendicular to both the velocity of the particle and the magnetic field, causing the particle to move in a circular path.
The radius of this circular path can be determined using the equation:
r = (mv)/(qB)
Where:
- r is the radius of the path
- m is the mass of the particle
- v is the velocity of the particle
- q is the charge of the particle
- B is the magnetic field strength
We are given that the two ions have the same charge and energy, meaning that their velocities (v) are the same. Therefore, the equation for the radius simplifies to:
r ∝ (m/q)
Since the charge (q) is the same for both ions, the radius is directly proportional to the mass (m). This means that as the mass of the ion increases, the radius of its path will also increase.
However, we are also given that the ions have different masses. This implies that the radius of their paths will be different, with the ion with the larger mass having a larger radius.
Therefore, we can conclude that the radii of the paths are **inversely proportional to the masses** of the ions. As the mass of an ion increases, its path radius will decrease, and vice versa.
Hence, the correct answer is option **C) Inversely proportional to their masses**.
Two ions of the same charge and energy but different mass are passing ...
As K.E.= q^2 B^2 R^2 / 2m
which implies
m is proportional to R^2
R is proportional to square root of mass
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