Introduction:
In order to determine the joules of electrical energy transferred per second by a 6V, 0.5A lamp, we need to use the formula for electrical power. Electrical power is given by the equation P = VI, where P is the power in watts, V is the voltage in volts, and I is the current in amperes.

Given:
Voltage (V) = 6V
Current (I) = 0.5A

Determining Power:
To find the power, we can substitute the given values into the formula P = VI.

P = 6V * 0.5A
P = 3W

Explanation:
The power of the lamp is determined to be 3 watts. This means that the lamp transfers electrical energy at a rate of 3 joules per second (since 1 watt is equivalent to 1 joule per second).

Calculation:
The calculation is straightforward:

Power (P) = 3W

Since the power is given in watts, we can directly conclude that the lamp transfers 3 joules of electrical energy per second.

Summary:
In summary, the 6V, 0.5A lamp transfers electrical energy at a rate of 3 joules per second. This calculation is based on the formula for electrical power, P = VI, where V represents voltage and I represents current. The power of the lamp is determined to be 3 watts, which is equivalent to 3 joules per second.