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A wheel of radius 0.4 m can rotate freely about its axis as shown in the figure. A string iswrapped over its rim and a mass of 4 kg is hung. An angular acceleration of 8 rad- s-2 is produced in it due to the torque. Then, moment of inertia of the wheel is (g = 10 ms-2)
Most Upvoted Answer
A wheel of radius 0.4 m can rotate freely about its axis as shown in t...
Given information:
- Radius of the wheel (r) = 0.4 m
- Mass hung on the wheel (m) = 4 kg
- Angular acceleration (α) = 8 rad/s^2
- Acceleration due to gravity (g) = 10 m/s^2
Calculating torque:
The torque (τ) acting on the wheel can be calculated using the formula:
τ = Iα
where τ is the torque, I is the moment of inertia, and α is the angular acceleration.
Rearranging the formula, we get:
I = τ/α
Substituting the given values, we have:
τ = m × g × r
I = (m × g × r) / α
Calculating torque:
Using the given values:
τ = 4 kg × 10 m/s^2 × 0.4 m = 16 Nm
Substituting the value of torque in the formula for moment of inertia, we have:
I = (16 Nm) / 8 rad/s^2 = 2 kgm^2
Final answer:
The moment of inertia of the wheel is 2 kgm^2.
- Radius of the wheel (r) = 0.4 m
- Mass hung on the wheel (m) = 4 kg
- Angular acceleration (α) = 8 rad/s^2
- Acceleration due to gravity (g) = 10 m/s^2
Calculating torque:
The torque (τ) acting on the wheel can be calculated using the formula:
τ = Iα
where τ is the torque, I is the moment of inertia, and α is the angular acceleration.
Rearranging the formula, we get:
I = τ/α
Substituting the given values, we have:
τ = m × g × r
I = (m × g × r) / α
Calculating torque:
Using the given values:
τ = 4 kg × 10 m/s^2 × 0.4 m = 16 Nm
Substituting the value of torque in the formula for moment of inertia, we have:
I = (16 Nm) / 8 rad/s^2 = 2 kgm^2
Final answer:
The moment of inertia of the wheel is 2 kgm^2.
Community Answer
A wheel of radius 0.4 m can rotate freely about its axis as shown in t...
Torque =moment of inertia× angular acceleration
I = torque /alpha
= force×radius / alpha
= 4× 10 × 0.4 /8
= 2 kg/ m^2
I = torque /alpha
= force×radius / alpha
= 4× 10 × 0.4 /8
= 2 kg/ m^2
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A wheel of radius 0.4 m can rotate freely about its axis as shown in the figure. A string iswrapped over its rim and a mass of 4 kg is hung. An angular acceleration of 8 rad- s-2 is produced in it due to the torque. Then, moment of inertia of the wheel is (g = 10 ms-2)
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A wheel of radius 0.4 m can rotate freely about its axis as shown in the figure. A string iswrapped over its rim and a mass of 4 kg is hung. An angular acceleration of 8 rad- s-2 is produced in it due to the torque. Then, moment of inertia of the wheel is (g = 10 ms-2) for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A wheel of radius 0.4 m can rotate freely about its axis as shown in the figure. A string iswrapped over its rim and a mass of 4 kg is hung. An angular acceleration of 8 rad- s-2 is produced in it due to the torque. Then, moment of inertia of the wheel is (g = 10 ms-2) covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A wheel of radius 0.4 m can rotate freely about its axis as shown in the figure. A string iswrapped over its rim and a mass of 4 kg is hung. An angular acceleration of 8 rad- s-2 is produced in it due to the torque. Then, moment of inertia of the wheel is (g = 10 ms-2).
A wheel of radius 0.4 m can rotate freely about its axis as shown in the figure. A string iswrapped over its rim and a mass of 4 kg is hung. An angular acceleration of 8 rad- s-2 is produced in it due to the torque. Then, moment of inertia of the wheel is (g = 10 ms-2) for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A wheel of radius 0.4 m can rotate freely about its axis as shown in the figure. A string iswrapped over its rim and a mass of 4 kg is hung. An angular acceleration of 8 rad- s-2 is produced in it due to the torque. Then, moment of inertia of the wheel is (g = 10 ms-2) covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A wheel of radius 0.4 m can rotate freely about its axis as shown in the figure. A string iswrapped over its rim and a mass of 4 kg is hung. An angular acceleration of 8 rad- s-2 is produced in it due to the torque. Then, moment of inertia of the wheel is (g = 10 ms-2).
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A wheel of radius 0.4 m can rotate freely about its axis as shown in the figure. A string iswrapped over its rim and a mass of 4 kg is hung. An angular acceleration of 8 rad- s-2 is produced in it due to the torque. Then, moment of inertia of the wheel is (g = 10 ms-2), a detailed solution for A wheel of radius 0.4 m can rotate freely about its axis as shown in the figure. A string iswrapped over its rim and a mass of 4 kg is hung. An angular acceleration of 8 rad- s-2 is produced in it due to the torque. Then, moment of inertia of the wheel is (g = 10 ms-2) has been provided alongside types of A wheel of radius 0.4 m can rotate freely about its axis as shown in the figure. A string iswrapped over its rim and a mass of 4 kg is hung. An angular acceleration of 8 rad- s-2 is produced in it due to the torque. Then, moment of inertia of the wheel is (g = 10 ms-2) theory, EduRev gives you an
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