A capacitor of capacity C₁ is charged by connecting it across a battery of e.m.f. V₀. The battery is then removed and the capacitor is connected in parallel with an uncharged capacitor of capacity C₂. The potential difference across this combination isa) C₂/C₁ + C₂ V₀ b) C₁/C₁ + C₂ V₀ c) C₁ + C₂/C₂ V₀ d) C₁ + C₂/C₁ V₀ Correct answer is option 'B'. Can you explain this answer?

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a)
C₂/C₁ + C₂ V₀
b)
C₁/C₁ + C₂ V₀
c)
C₁ + C₂/C₂ V₀
d)
C₁ + C₂/C₁ V₀

Correct answer is option 'B'. Can you explain this answer?

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A capacitor of capacity C₁ is charged by connecting it across a batter...

The voltage of the capacitorC1 is V0= q1/C1 and the voltage of the uncharged capacitor C2 is 0 as its charge is 0.

When the two capacitors are electrically connected then the charge will flow from higher potential to lower potential till the difference of potential ceases to exist. Let the common potential of C1 and C2 be V. Assuming no loss charge during the charge sharing process, Total charge before connection = Total charge after connection

i.e C1V0 + 0 = C1V + C2V = (C1+C2)V or V= Vo C1/(C1+C2)

Final potential V= Vo C1/(C1+C2)

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A capacitor of capacity C₁ is charged by connecting it across a battery of e.m.f. V₀. The battery is then removed and the capacitor is connected in parallel with an uncharged capacitor of capacity C₂. The potential difference across this combination isa) C₂/C₁ + C₂ V₀ b) C₁/C₁ + C₂ V₀ c) C₁ + C₂/C₂ V₀ d) C₁ + C₂/C₁ V₀ Correct answer is option 'B'. Can you explain this answer?

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