Nine students of a class contribute a certain sum. Seven of them give ...
Average = sum/n
Average of 9 students = x
n = 9
x = sum/9
Seven of them give Rs. 5 = 7 * 5 = 35
35+(5+x)+(9+x) ∴ other two give Rs. 5 and Rs. 9 more than the average contribution
x = 35+(5+x)+(9+x)/9
x = 49+2x/9
9x = 49 + 2x
9x - 2x = 49
7x = 49
x = 7
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Nine students of a class contribute a certain sum. Seven of them give ...
let average contribution is x 8th boy gave=x+5 9th boy gave=x+9 average contribution =(5+5+5+5+5+5+5+x+5+x+9)÷9 hence (5+5+5+5+5+5+5+x+5+x+9)÷9=x x=7
Nine students of a class contribute a certain sum. Seven of them give ...
Given:
- Seven students gave Rs. 5 each.
- Two students gave Rs. 5 more than the average contribution of all 9 students.
To find:
- The average contribution of the class of 9 students.
Solution:
Let's assume the average contribution of all 9 students is 'x'.
Total contribution of seven students = 7 × 5 = 35
Total contribution of two students = 2 × (x + 5)
Total contribution of all 9 students = 35 + 2(x + 5)
The average contribution of all 9 students can be calculated as:
(x1 + x2 + x3 + x4 + x5 + x6 + x7 + (x8 + 5) + (x9 + 5))/9 = (7x + 2x + 70)/9 = (9x + 70)/9
We know that the average contribution of all 9 students is 'x', so we can equate the above equation to 'x' and solve for it:
(9x + 70)/9 = x
9x + 70 = 9x
70 = 9x - 9x
70 = 0
This is not possible, so there must be an error in the question. However, if we assume that the two students gave Rs. 5 less than the average contribution of all 9 students, then we can solve for the average contribution:
Total contribution of two students = 2 × (x - 5)
Total contribution of all 9 students = 35 + 2(x - 5)
The average contribution of all 9 students can be calculated as:
(x1 + x2 + x3 + x4 + x5 + x6 + x7 + (x8 - 5) + (x9 - 5))/9 = (7x + 2x - 20)/9 = (9x - 20)/9
We know that the average contribution of all 9 students is 'x', so we can equate the above equation to 'x' and solve for it:
(9x - 20)/9 = x
9x - 20 = 9x
-20 = 0
This is not possible either, so there seems to be an error in the question. However, if we assume that the contribution of the two students is Rs. 9 more than the average contribution of all 9 students, then we can solve for the average contribution:
Total contribution of two students = 2 × (x + 9)
Total contribution of all 9 students = 35 + 2(x + 9)
The average contribution of all 9 students can be calculated as:
(x1 + x2 + x3 + x4 + x5 + x6 + x7 + (x8 + 9) + (x9 + 9))/9 = (7x + 2x + 18)/9 = (9x + 18)/9
We know that the average contribution of all 9 students is 'x', so we can equate the above equation to 'x' and solve for it:
(9x + 18)/9 = x
9x + 18 = 9x
18 = 0
This is not possible either, so there seems to be an error in the question