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The moment of inertia of a uniform circular dise of radius a about an axis perpendicular to its plane and passing through a point on its edge is l1, and the moment of inertia of that disc about an axis perpendicular to the plane and passing through the center is l2. The ratio l1/l2 equals: a)3 B)1 C)4 D)6?
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The moment of inertia of a uniform circular dise of radius a about an ...
Ratio of Moment of Inertia of Circular Disc

Given:
- Moment of inertia about edge axis (I1) = l1
- Moment of inertia about center axis (I2) = l2

Formula:
- Moment of inertia for a disc about edge axis: I1 = (1/2) * m * a^2
- Moment of inertia for a disc about center axis: I2 = (1/4) * m * a^2

Calculations:
- l1 = (1/2) * m * a^2
- l2 = (1/4) * m * a^2

Ratio Calculation:
l1/l2 = [(1/2) * m * a^2] / [(1/4) * m * a^2]
l1/l2 = 2

Conclusion:
Therefore, the ratio of moment of inertia of a uniform circular disc about an axis perpendicular to its plane and passing through a point on its edge to the moment of inertia about an axis passing through the center is 2. Hence, the correct answer is not provided in the options given.
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The moment of inertia of a uniform circular dise of radius a about an axis perpendicular to its plane and passing through a point on its edge is l1, and the moment of inertia of that disc about an axis perpendicular to the plane and passing through the center is l2. The ratio l1/l2 equals: a)3 B)1 C)4 D)6?
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