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An electron remains undeflected when passing perpendicular to mutually perpendicular electric and magnetic fields. If the magnetic field is 8 Gauss and elecric field is 4000 V/m, the velocity of the electron is
  • a)
    2 x 106 ms−1
  • b)
    5 x 106 ms−1
  • c)
    6 x 106 ms−1
  • d)
    7.5 x 106 ms−1
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
An electron remains undeflected when passing perpendicular to mutually...
B) 4 x 106 ms

c) 8 x 106 ms

d) 1 x 106 ms

We can use the formula for the magnetic force on a charged particle:

F = qvB

where F is the force, q is the charge (which is the charge of an electron), v is the velocity, and B is the magnetic field.

We can also use the formula for the electric force on a charged particle:

F = qE

where F is the force, q is the charge, and E is the electric field.

Since the electron is undeflected, the magnetic force must be equal and opposite to the electric force:

qvB = qE

Solving for v, we get:

v = E/B

Plugging in the values given, we get:

v = (4000 V/m)/(8 Gauss) = (4000 V/m)/(8 x 10^-4 T) = 5 x 10^6 m/s

So the answer is (c) 8 x 10^6 m/s.
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Community Answer
An electron remains undeflected when passing perpendicular to mutually...
Electric force balances magnetic force. so net force on an electron will be zero.
qE=qvB
v=E/B 1gauss=10^-4 Tesla
so v=5×10^6 m/s
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An electron remains undeflected when passing perpendicular to mutually perpendicular electric and magnetic fields. If the magnetic field is 8 Gauss and elecric field is 4000 V/m, the velocity of the electron isa)2 x 106 ms−1b)5 x 106 ms−1c)6 x 106 ms−1d)7.5 x 106 ms−1Correct answer is option 'B'. Can you explain this answer?
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