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A ray of light enters a rectangular glass slab of refractive index 1.5. It is found that the ray emerges from the opposite face of the slab without being displaced. If its speed in air is 3 x 10^8 ms^-1 then what is its speed in glass?
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A ray of light enters a rectangular glass slab of refractive index 1.5...
Given data:
- Refractive index of glass (μ) = 1.5
- Speed of light in air (v1) = 3 x 10^8 m/s

Explanation:

Snell's Law:
- When light enters a different medium, it changes speed according to Snell's Law: n1sinθ1 = n2sinθ2
- In this case, light enters the glass slab from air, so n1 = 1 (for air) and n2 = 1.5 (for glass). Since the ray emerges without being displaced, the angle of incidence (θ1) is equal to the angle of refraction (θ2).

Speed of light in different mediums:
- The speed of light in a medium is inversely proportional to the refractive index of that medium. Mathematically, v = c / μ, where c is the speed of light in vacuum.
- Therefore, the speed of light in glass (v2) can be calculated as v2 = c / μ = (3 x 10^8) / 1.5 = 2 x 10^8 m/s

Conclusion:
- The speed of light in the glass slab is 2 x 10^8 m/s.
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A ray of light enters a rectangular glass slab of refractive index 1.5. It is found that the ray emerges from the opposite face of the slab without being displaced. If its speed in air is 3 x 10^8 ms^-1 then what is its speed in glass?
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