In a cricket matchKumble took three wickets less than twice the number...
Let the number of wickets taken by Srinath be x then the number of wickets taken by Kumble will be 2x−3
According to question, x (2x−3) = 20
⇒ 2x2−3x−20 = 0
⇒ 2x2−8x+5x−20 = 0
⇒ 2x(x−4)+5(x−4) = 0
⇒ (x−4)(2x+5) = 0
⇒ x−4 = 0and 2x+5 = 0
Therefore, number of wickets taken by Srinath is 4.
Then number of wickets taken by Kumble = 2 x 4 - 3 = 5
View all questions of this test
In a cricket matchKumble took three wickets less than twice the number...
let the no of wickets taken by srinath be x
no of wickets taken by kumble 2x-3
product of their wickets = 20
so X(2X-3) = 20
2xsquare - 3x - 20 = 0
2xsquare - 8x + 5x -20 = 0
2x(x-4) + 5(x-4) = 0
(2x+5)(x-4) = 0
x = -5/2 x = 4
-5/2 rejected because wickets cannot be negative so no of wicketsvtaken by srinath = 4 and kumble is 5
In a cricket matchKumble took three wickets less than twice the number...
To solve this problem, let's assume that the number of wickets taken by Srinath is x.
According to the given information, Kumble took three wickets less than twice the number of wickets taken by Srinath, which can be expressed as:
Number of wickets taken by Kumble = 2x - 3
Now, we are also given that the product of the number of wickets taken by Kumble and Srinath is 20, which can be expressed as:
(2x - 3) * x = 20
To solve this equation, we can simplify it:
2x^2 - 3x - 20 = 0
Now, we need to factorize this quadratic equation:
(2x + 5)(x - 4) = 0
Setting each factor equal to zero, we get:
2x + 5 = 0 or x - 4 = 0
Solving these equations, we find:
2x = -5 or x = 4
Since the number of wickets cannot be negative, we discard the solution x = -5. Therefore, the number of wickets taken by Srinath is x = 4.
Now, we can substitute this value back into the equation for Kumble's wickets:
Number of wickets taken by Kumble = 2x - 3 = 2(4) - 3 = 8 - 3 = 5
Hence, the correct answer is option A) 5, as Kumble took 5 wickets.