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A uniform cylinder of mass M and radius R rolls without slipping down a slope of angle θ to the horizontal. The cylinder is connected to a spring constant K while the other end of the spring is connected to a rigid support at P. The cylinder is released when the spring is unstretched. The maximum distance that the cylinder travels is
  • a)
  • b)
  • c)
  • d)
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
A uniform cylinder of mass M and radius R rolls without slipping down ...

Potential energy of spring 
Workdone by gravity = mg sineθx.
By energy conservations, 
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Most Upvoted Answer
A uniform cylinder of mass M and radius R rolls without slipping down ...
Yes option C is correct... solution: 'g' be the acceleration due to gravity.. potential energy of stretched spring=1/2Kx^2...loss in gravitational potential energy=mgh=mg(x sin theta)..therefore; 1/2Kx^2=mg(x sin theta) x=2mgsin theta/K...hope u clear...!👍👍
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Community Answer
A uniform cylinder of mass M and radius R rolls without slipping down ...
Potential energy of spring
Workdone by gravity = mg sineθx.
By energy conservations,
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A uniform cylinder of mass M and radius R rolls without slipping down a slope of angle θ to the horizontal. The cylinder is connected to a spring constant K while the other end of the spring is connected to a rigid support at P. The cylinder is released when the spring is unstretched. The maximum distance that the cylinder travels isa)b)c)d)Correct answer is option 'C'. Can you explain this answer?
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