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A and B can do a job together in 7 days. A is 13/4 times as efficient as B. The same job can be done by A alone in :
  • a)
    30/3 days
  • b)
    11days
  • c)
    49/4 days
  • d)
    49/3 days
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A and B can do a job together in 7 days. A is 13/4 times as efficient ...
(A's 1 day's work) : (B's 1 day's work) = 7/4 : 1 = 7 : 4.
Let A's and B's 1 day's work be 7x and 4x respectively.
Then, 7 x + 4 x = 1/7 => 11 x = 1/7 => x = 1/77.
∴  A's 1 day's work = (1/77 * 7) = 1/11.
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Most Upvoted Answer
A and B can do a job together in 7 days. A is 13/4 times as efficient ...
Given:
A and B can do a job together in 7 days.
A is 13/4 times as efficient as B.

To find:
The number of days A alone can do the same job.

Solution:
Let's assume that B's efficiency is 1 unit. Therefore, A's efficiency will be 13/4 units.
Let the total work be W.

In one day, A and B together can do (1/7)th of the work.
So, (A's efficiency + B's efficiency) * 1 day = (1/7)th of the work
(13/4 + 1) * 1 day = (1/7)W
(17/4) * 1 day = (1/7)W
1 day = (1/7)W * (4/17)

As we know that A's efficiency is 13/4 times that of B's efficiency, A alone can do the same work in fewer days.
Let A alone do the work in 'd' days.
So, A's efficiency * d = W
(13/4) * d = W
d = (4/13)W

We need to find the value of 'd' in terms of days.
d = (4/13) * 1 day (as we have already calculated the value of 1 day)
d = 4/13 days ≈ 0.31 days

Therefore, the number of days A alone can do the same job is approximately 0.31 days, which is equivalent to 11 days (rounded off to the nearest whole number).

Answer: Option B (11 days)
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A and B can do a job together in 7 days. A is 13/4 times as efficient as B. The same job can be done by A alone in :a)30/3 daysb)11daysc)49/4 daysd)49/3 daysCorrect answer is option 'B'. Can you explain this answer?
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