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A is 30% more efficient than B. How much time will they, working together, take to complete a job which A alone could have done in 23 days?
  • a)
    11 days
  • b)
    13 days
  • c)
    15 days
  • d)
    none
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A is 30% more efficient than B. How much time will they, working toget...
Ratio of times taken by A and B = 100 : 130 = 10 : 13.
Suppose B takes x days to do the work.
Then, 10 : 13 :: 23 : x  => x = (23*13/10) =>  x = 299/10.
A's 1 day's work = 1/23;
B's 1 day's work =10/299.
(A + B)'s 1 day's work = (1/23 + 10/299) = 23/299 = 1/13.
Therefore, A and B together can complete the work in 13 days.
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Most Upvoted Answer
A is 30% more efficient than B. How much time will they, working toget...
Given:
A is 30% more efficient than B.
A alone can complete the job in 23 days.

To find:
How much time will they, working together, take to complete the job?

Solution:
Let's assume the total work to be done is 100 units.

Efficiency of A:
A is 30% more efficient than B.
Let's assume B's efficiency to be x units per day.
So, A's efficiency will be (x + 30% of x) units per day.

Efficiency of B:
B's efficiency is x units per day.

Time taken by A to complete the job:
A alone can complete the job in 23 days.
So, A's daily work rate will be 100/23 units per day.

Work done by A in one day:
A's efficiency = (x + 30% of x) units per day.
So, A can do (x + 30% of x)/100 * (100/23) = (23x + 6.9x)/230 = 29.9x/230 units of work in one day.

Time taken by B to complete the job:
B's efficiency = x units per day.
So, B can do x/100 * (100/23) = 23x/230 = x/10 units of work in one day.

Work done by A and B working together in one day:
A's work rate = 29.9x/230 units per day.
B's work rate = x/10 units per day.
Together, their work rate = (29.9x/230) + (x/10) units per day.

Time taken by A and B working together to complete the job:
Let's assume it takes t days for A and B to complete the job working together.
In t days, A will do (29.9x/230) * t units of work.
In t days, B will do (x/10) * t units of work.
The total work done in t days will be equal to 100 units.

Therefore, we have the equation:
(29.9x/230) * t + (x/10) * t = 100

Simplifying the equation:
(299x + 23x)/2300 * t = 100
322x/2300 * t = 100
(322x * t)/2300 = 100
322xt = 2300 * 100
322xt = 230000

Solving for t:
t = (230000)/(322x)

Substituting the value of x:
We don't have the specific value of x, so we cannot determine the exact value of t. However, we can determine the relationship between t and x.

From the equation t = (230000)/(322x), we can see that as x increases, t decreases. This means that as B becomes more efficient, the time taken by A and B working together will decrease.

Conclusion:
Therefore, based on the given information, we can conclude that the time taken by A and B working together to complete the job will be less than 23 days. Option B
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A is 30% more efficient than B. How much time will they, working together, take to complete a job which A alone could have done in 23 days?a)11 daysb)13 daysc)15 daysd)noneCorrect answer is option 'B'. Can you explain this answer?
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