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20 ml of decinormal solution of NaOH neutralises 25 ml of a solution of dibasic acid containing 3g. of the acid per 500 ml. The Molecular weight of the acid is?
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20 ml of decinormal solution of NaOH neutralises 25 ml of a solution o...
Given data:
- Volume of NaOH solution = 20 ml
- Volume of dibasic acid solution = 25 ml
- Concentration of dibasic acid = 3g per 500 ml
- Volume of dibasic acid solution in the reaction = 25 ml
Calculations:
Determine the number of moles of NaOH:
- NaOH is a monobasic base, so it reacts with 1 mole of acid.
- Normality of NaOH solution = 0.1 N (decinormal solution)
- Moles of NaOH = Normality x Volume (in liters)
- Moles of NaOH = 0.1 x (20/1000) = 0.002 moles
Determine the number of moles of dibasic acid:
- Since 1 mole of NaOH reacts with 1 mole of acid, the number of moles of dibasic acid is equal to the number of moles of NaOH.
- Moles of dibasic acid = 0.002 moles
Calculate the molecular weight of the dibasic acid:
- Mass of dibasic acid used in the reaction = 3g
- Moles of dibasic acid = Mass/Molecular weight
- Molecular weight = Mass/Moles
- Molecular weight = 3/0.002 = 150 g/mol
Therefore, the molecular weight of the dibasic acid is 150 g/mol.
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20 ml of decinormal solution of NaOH neutralises 25 ml of a solution of dibasic acid containing 3g. of the acid per 500 ml. The Molecular weight of the acid is?
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20 ml of decinormal solution of NaOH neutralises 25 ml of a solution of dibasic acid containing 3g. of the acid per 500 ml. The Molecular weight of the acid is? for UPSC 2025 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about 20 ml of decinormal solution of NaOH neutralises 25 ml of a solution of dibasic acid containing 3g. of the acid per 500 ml. The Molecular weight of the acid is? covers all topics & solutions for UPSC 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 20 ml of decinormal solution of NaOH neutralises 25 ml of a solution of dibasic acid containing 3g. of the acid per 500 ml. The Molecular weight of the acid is?.
20 ml of decinormal solution of NaOH neutralises 25 ml of a solution of dibasic acid containing 3g. of the acid per 500 ml. The Molecular weight of the acid is? for UPSC 2025 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about 20 ml of decinormal solution of NaOH neutralises 25 ml of a solution of dibasic acid containing 3g. of the acid per 500 ml. The Molecular weight of the acid is? covers all topics & solutions for UPSC 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 20 ml of decinormal solution of NaOH neutralises 25 ml of a solution of dibasic acid containing 3g. of the acid per 500 ml. The Molecular weight of the acid is?.
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