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An object is placed at distance of 15 cm from a diverging lens of focal length 6 cm . find the nature position of the image?
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An object is placed at distance of 15 cm from a diverging lens of foca...
Calculation of Image Position and Nature
- Given data:
- Object distance (u) = -15 cm (negative as it is on the opposite side of the lens)
- Focal length (f) = -6 cm (for a diverging lens, focal length is negative)
- Using the lens formula:
- 1/f = 1/v - 1/u
- Substituting the given values, we get:
- 1/-6 = 1/v - 1/-15
- -1/6 = 1/v + 1/15
- -1/6 - 1/15 = 1/v
- -5/30 - 2/30 = 1/v
- -7/30 = 1/v
- v = -30/7 cm
- Therefore, the image is formed at a distance of -30/7 cm from the lens.
Determination of Nature of Image
- Since the image distance (v) is negative, the image is formed on the same side as the object.
- The negative sign indicates that the image is virtual and upright.
- The diverging lens always forms virtual images that are diminished in size.
- Given data:
- Object distance (u) = -15 cm (negative as it is on the opposite side of the lens)
- Focal length (f) = -6 cm (for a diverging lens, focal length is negative)
- Using the lens formula:
- 1/f = 1/v - 1/u
- Substituting the given values, we get:
- 1/-6 = 1/v - 1/-15
- -1/6 = 1/v + 1/15
- -1/6 - 1/15 = 1/v
- -5/30 - 2/30 = 1/v
- -7/30 = 1/v
- v = -30/7 cm
- Therefore, the image is formed at a distance of -30/7 cm from the lens.
Determination of Nature of Image
- Since the image distance (v) is negative, the image is formed on the same side as the object.
- The negative sign indicates that the image is virtual and upright.
- The diverging lens always forms virtual images that are diminished in size.
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An object is placed at distance of 15 cm from a diverging lens of focal length 6 cm . find the nature position of the image?
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An object is placed at distance of 15 cm from a diverging lens of focal length 6 cm . find the nature position of the image? for Class 10 2024 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about An object is placed at distance of 15 cm from a diverging lens of focal length 6 cm . find the nature position of the image? covers all topics & solutions for Class 10 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An object is placed at distance of 15 cm from a diverging lens of focal length 6 cm . find the nature position of the image?.
An object is placed at distance of 15 cm from a diverging lens of focal length 6 cm . find the nature position of the image? for Class 10 2024 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about An object is placed at distance of 15 cm from a diverging lens of focal length 6 cm . find the nature position of the image? covers all topics & solutions for Class 10 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An object is placed at distance of 15 cm from a diverging lens of focal length 6 cm . find the nature position of the image?.
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