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An object placed at a distance of 15 cm from a diverging mirror of focal length 6 cm . find nature and position?
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An object placed at a distance of 15 cm from a diverging mirror of foc...
Given Data:
- Object distance (u) = -15 cm
- Focal length (f) = -6 cm (negative because it is a diverging mirror)

Calculations:
- Using the mirror formula: 1/f = 1/v + 1/u
- Substituting the values: 1/-6 = 1/v + 1/-15
- Solving for v, we get: v = -10 cm

Position and Nature of Image:
- The image is formed at a distance of -10 cm from the mirror.
- Since the image distance is negative, the image is formed on the same side as the object (virtual image).
- The image distance is less than the focal length, so the image is virtual, erect, and diminished.

Conclusion:
- The nature of the image formed by the diverging mirror is virtual, erect, and diminished.
- The image is formed at a distance of 10 cm from the mirror on the same side as the object.
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An object placed at a distance of 15 cm from a diverging mirror of focal length 6 cm . find nature and position?
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