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Show that the square of any positive integer is either of the form 4q or 4q+1 for some integer?
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Show that the square of any positive integer is either of the form 4q ...
Proof:

1. Square of an Even Integer:
When we square an even integer, say 2n, we get (2n)^2 = 4n^2. This is clearly of the form 4q where q = n^2.

2. Square of an Odd Integer:
When we square an odd integer, say 2n+1, we get (2n+1)^2 = 4n^2 + 4n + 1 = 4(n^2 + n) + 1. This is of the form 4q+1 where q = n^2 + n.

Conclusion:
Therefore, the square of any positive integer can be represented in the form 4q or 4q+1 for some integer q. This is true for both even and odd integers.
This proof shows that any positive integer when squared will result in a number that is either of the form 4q or 4q+1. The key idea is to consider the cases of even and odd integers separately and demonstrate that the resulting square follows the specified forms. This proof provides a clear and concise explanation of the pattern observed in the squares of positive integers.
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Show that the square of any positive integer is either of the form 4q or 4q+1 for some integer?
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