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Suppose sum of two smallest positive divisors of an integer N is 6, while the sum of the two largest positive divisors of N is 858. What is the sum of the digits of N ?
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Suppose sum of two smallest positive divisors of an integer N is 6, wh...
Given Information:
- Sum of two smallest positive divisors of N is 6
- Sum of two largest positive divisors of N is 858

Explanation:

Finding the Divisors:
- Let the smallest divisors of N be a and b, where a < />
- Let the largest divisors of N be c and d, where c < />

Sum of smallest divisors:
a + b = 6

Sum of largest divisors:
c + d = 858

Relationship between divisors:
- The product of divisors of N is equal to N
- N = a * b = c * d

Solving for N:
- From a + b = 6, we can say that a = 2 and b = 4
- From c + d = 858, we can say that c = 429 and d = 429
- Therefore, N = a * b = 2 * 4 = 8

Sum of Digits of N:
- Sum of digits of N = 8
Therefore, the sum of the digits of N is 8.
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Suppose sum of two smallest positive divisors of an integer N is 6, while the sum of the two largest positive divisors of N is 858. What is the sum of the digits of N ?
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