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With ammoniacal cuprous chloride solution, a reddish brown precipitate is obtained on treating with
- a)CH4
- b)C2H4
- c)C2H2
- d)C3H6
Correct answer is option 'C'. Can you explain this answer?
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Most Upvoted Answer
With ammoniacal cuprous chloride solution, a reddish brown precipitate...
All terminal alkynes behave as very weak acids. They react with NaNH2, Na, Tollens' reagent, and ammoniacal cuprous chloride solution.
The reaction of ammoniacal cuprous chloride solution with terminal alkyne is as follows:
The reaction of ammoniacal cuprous chloride solution with terminal alkyne is as follows:
This reaction shows the acidic nature of alkynes.
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Community Answer
With ammoniacal cuprous chloride solution, a reddish brown precipitate...
Explanation:
Ammoniacal cuprous chloride solution:
When cuprous chloride (CuCl) is dissolved in a solution of ammonia (NH3), it forms ammoniacal cuprous chloride solution.
Reaction:
CuCl + 4NH3 → [Cu(NH3)4]Cl
Test for alkynes:
Alkynes are unsaturated hydrocarbons with a carbon-carbon triple bond. One of the common tests for alkynes is the formation of a reddish-brown precipitate with ammoniacal cuprous chloride solution.
Reaction with acetylene (C2H2):
When acetylene (C2H2) reacts with ammoniacal cuprous chloride solution, it forms a reddish-brown precipitate due to the formation of copper acetylide.
Reaction:
2[Cu(NH3)4]Cl + C2H2 → 2Cu2C2 + 8NH4Cl
Therefore, the correct answer is option C: C2H2 (acetylene). Acetylene is an alkyne that gives a characteristic reddish-brown precipitate with ammoniacal cuprous chloride solution.
Ammoniacal cuprous chloride solution:
When cuprous chloride (CuCl) is dissolved in a solution of ammonia (NH3), it forms ammoniacal cuprous chloride solution.
Reaction:
CuCl + 4NH3 → [Cu(NH3)4]Cl
Test for alkynes:
Alkynes are unsaturated hydrocarbons with a carbon-carbon triple bond. One of the common tests for alkynes is the formation of a reddish-brown precipitate with ammoniacal cuprous chloride solution.
Reaction with acetylene (C2H2):
When acetylene (C2H2) reacts with ammoniacal cuprous chloride solution, it forms a reddish-brown precipitate due to the formation of copper acetylide.
Reaction:
2[Cu(NH3)4]Cl + C2H2 → 2Cu2C2 + 8NH4Cl
Therefore, the correct answer is option C: C2H2 (acetylene). Acetylene is an alkyne that gives a characteristic reddish-brown precipitate with ammoniacal cuprous chloride solution.
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With ammoniacal cuprous chloride solution, a reddish brown precipitate is obtained on treating witha)CH4b)C2H4c)C2H2d)C3H6Correct answer is option 'C'. Can you explain this answer?
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