In a mixture 60 litres, the ratio of milk and water 2 : 1. If this ratio is to be 1 : 2, then the quanity of water to be further added is:a)20 litresb)30 litresc)40 litresd)60 litresCorrect answer is option 'D'. Can you explain this answer?

Question

Answer

In first case ratio is 2:1 that is milk is 40 and water is 20...in next case ratio is 1:2...here water is being added but milk is constant that means it will.be 40 in case 2 for.milk also so that makes it like if 1 is for 40 then 2 will be 80...that is first was 20 and now 80 ..so 60.litres is added

Answer

Milk : water
.... 2 : 1 = 60 litres.
milk constant.
so, 40 litres : x litres water = 1: 2
so, extra water = 80-20= 60 litres

Answer

Because in 1st and 2nd milk n water ratio is changed by 2:1 to 1:2 but not the total volume ...like if we do 2×4=8 n 4×2=8 ..ans are same just representation is different that why 'D' is correct

Answer

4

Answer

60 liters

Answer

Answer 5

Answer

Is the fraction of wine in the first vessel and d is the fraction of water in the second vessel, find the new fractions of wine in the first vessel and water in the second vessel.

Initially, the first vessel contains a*c litres of wine and (1-c)a litres of water, and the second vessel contains b*(1-d) litres of wine and b*d litres of water.

When c litres are taken out of the first vessel, the amount of wine left in the first vessel is (a*c - c) litres, and the amount of water left is ((1-c)a + c) litres. Similarly, when c litres are added to the second vessel, the amount of wine in the second vessel becomes (b*(1-d) + c*d) litres, and the amount of water becomes (b*d - c).

The new fraction of wine in the first vessel is:

[(a*c - c)/(a - c)] / [(a*c - c)/(a - c) + [(1-c)a + c]/(a - c)]
= (a*c - c)/[a*c - c + (1-c)a + c]
= ac / [ac + (1-c)a]
= c

Similarly, the new fraction of water in the second vessel is:

[(b*d - c)/(b - c)] / [(b*(1-d) + c*d)/(b - c) + (b*d - c)/(b - c)]
= (b*d - c) / [b*(1-d) + c*d + b*d - c]
= (b*d - c) / [2bd - c + cd]
= d - c/[2d - c]

Therefore, the new fraction of wine in the first vessel is c, and the new fraction of water in the second vessel is d - c/[2d - c].

Answer

Bro the answer is in the question itself read the line again ''then the QUANTUTY OF WATER FURTHER ADDED IS..

Answer

Answer

Given, 60 liters mixture of milk,
the ratio for 2:1 out of 1:2 is verified as
milk = 2% = 20÷2 = 10, water = 10% added
milk + water = 10+10.
for above 60 liters with in 1:2 turns
= 60-10+10 = 50+10
= 60 liters.
the quality for 10% water added = 60 liters .

Answer

60lt

Answer

The amount of wine in the first vessel after the transfer is:

a - c + (c*b)/(a+b)

The amount of water in the second vessel after the transfer is:

b - c + (c*a)/(a+b)

Note that the total amount of liquid in each vessel remains constant, as c litres were transferred between them.

Similar Quant Doubts

A can contains 40 litres of milk at Rs 3.5 per litre. How much water must be added to this can so that the cost of milk reduces to Rs 2 per litre?

A mixture contains milk and water in the ratio 2 : 3 and the other contains them in the ratio 3 : 1 respectively. What weight of 2nd mixture must be taken so as to make a third mixture 7 litres in weight with 70% milk?

A mixture of 70 litres of alcohol and water contains 10% of water. How much water must be added to the above mixture to make the water 12.5% of the resulting mixture?

Top Courses for Quant

Related Content

Quant Courses

Related Exams

Related Question Answers

Related Searches

Company