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The electrostatic force b/w two identical charges is 0.9N. Distance b/w the changes is 10m. Find the magnitute of each change?
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The electrostatic force b/w two identical charges is 0.9N. Distance b/...
Explanation:
Given data:
- Electrostatic force between two identical charges: 0.9 N
- Distance between the charges: 10 m
Formula:
The electrostatic force between two charges can be calculated using Coulomb's law:
\[ F = \frac{k \cdot |q_1 \cdot q_2|}{r^2} \]
Where:
- \( F \) is the electrostatic force
- \( k \) is the electrostatic constant (\( 9 \times 10^9 Nm^2/C^2 \))
- \( q_1 \) and \( q_2 \) are the magnitudes of the charges
- \( r \) is the distance between the charges
Solution:
Given that the electrostatic force is 0.9 N and the distance between the charges is 10 m. We can rearrange the formula to solve for the magnitude of each charge:
\[ q_1 \cdot q_2 = \frac{F \cdot r^2}{k} \]
Plugging in the values:
\[ q_1 \cdot q_2 = \frac{0.9 \cdot (10)^2}{9 \times 10^9} \]
\[ q_1 \cdot q_2 = \frac{90}{9 \times 10^9} \]
\[ q_1 \cdot q_2 = 10 \times 10^{-9} \]
\[ q_1 \cdot q_2 = 10^{-8} \]
Since the charges are identical, \( q_1 = q_2 \). Therefore, each charge has a magnitude of:
\[ q_1 = q_2 = \sqrt{10^{-8}} \]
\[ q_1 = q_2 = 10^{-4} \]
Therefore, the magnitude of each charge is \( 10^{-4} C \).
Given data:
- Electrostatic force between two identical charges: 0.9 N
- Distance between the charges: 10 m
Formula:
The electrostatic force between two charges can be calculated using Coulomb's law:
\[ F = \frac{k \cdot |q_1 \cdot q_2|}{r^2} \]
Where:
- \( F \) is the electrostatic force
- \( k \) is the electrostatic constant (\( 9 \times 10^9 Nm^2/C^2 \))
- \( q_1 \) and \( q_2 \) are the magnitudes of the charges
- \( r \) is the distance between the charges
Solution:
Given that the electrostatic force is 0.9 N and the distance between the charges is 10 m. We can rearrange the formula to solve for the magnitude of each charge:
\[ q_1 \cdot q_2 = \frac{F \cdot r^2}{k} \]
Plugging in the values:
\[ q_1 \cdot q_2 = \frac{0.9 \cdot (10)^2}{9 \times 10^9} \]
\[ q_1 \cdot q_2 = \frac{90}{9 \times 10^9} \]
\[ q_1 \cdot q_2 = 10 \times 10^{-9} \]
\[ q_1 \cdot q_2 = 10^{-8} \]
Since the charges are identical, \( q_1 = q_2 \). Therefore, each charge has a magnitude of:
\[ q_1 = q_2 = \sqrt{10^{-8}} \]
\[ q_1 = q_2 = 10^{-4} \]
Therefore, the magnitude of each charge is \( 10^{-4} C \).
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The electrostatic force b/w two identical charges is 0.9N. Distance b/w the changes is 10m. Find the magnitute of each change?
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The electrostatic force b/w two identical charges is 0.9N. Distance b/w the changes is 10m. Find the magnitute of each change? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about The electrostatic force b/w two identical charges is 0.9N. Distance b/w the changes is 10m. Find the magnitute of each change? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The electrostatic force b/w two identical charges is 0.9N. Distance b/w the changes is 10m. Find the magnitute of each change?.
The electrostatic force b/w two identical charges is 0.9N. Distance b/w the changes is 10m. Find the magnitute of each change? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about The electrostatic force b/w two identical charges is 0.9N. Distance b/w the changes is 10m. Find the magnitute of each change? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The electrostatic force b/w two identical charges is 0.9N. Distance b/w the changes is 10m. Find the magnitute of each change?.
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