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A weight of 200 kg is suspended by vertical wire of length 600.5 cm The area of cross-section of wire is 1mm^2 when the load is removed the wire contracts by 0.5 cm the youngs modulus of material of wire wil be?
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A weight of 200 kg is suspended by vertical wire of length 600.5 cm Th...
Given data:
- Load (W) = 200 kg
- Length of wire (L) = 600.5 cm = 6.005 m
- Area of cross-section (A) = 1 mm^2 = 1 x 10^-6 m^2
- Contraction in wire (ΔL) = 0.5 cm = 0.005 m
Calculating stress:
Stress (σ) = Load/ Area
σ = W/A
σ = 200 kg x 9.81 m/s^2 / 1 x 10^-6 m^2
σ = 1.962 x 10^6 N/m^2
Calculating strain:
Strain (ε) = ΔL / L
ε = 0.005 m / 6.005 m
ε = 8.32 x 10^-4
Calculating Young's modulus:
Young's modulus (Y) = Stress / Strain
Y = σ / ε
Y = 1.962 x 10^6 N/m^2 / 8.32 x 10^-4
Y = 2.36 x 10^9 N/m^2
Therefore, the Young's modulus of the material of the wire is 2.36 x 10^9 N/m^2.
- Load (W) = 200 kg
- Length of wire (L) = 600.5 cm = 6.005 m
- Area of cross-section (A) = 1 mm^2 = 1 x 10^-6 m^2
- Contraction in wire (ΔL) = 0.5 cm = 0.005 m
Calculating stress:
Stress (σ) = Load/ Area
σ = W/A
σ = 200 kg x 9.81 m/s^2 / 1 x 10^-6 m^2
σ = 1.962 x 10^6 N/m^2
Calculating strain:
Strain (ε) = ΔL / L
ε = 0.005 m / 6.005 m
ε = 8.32 x 10^-4
Calculating Young's modulus:
Young's modulus (Y) = Stress / Strain
Y = σ / ε
Y = 1.962 x 10^6 N/m^2 / 8.32 x 10^-4
Y = 2.36 x 10^9 N/m^2
Therefore, the Young's modulus of the material of the wire is 2.36 x 10^9 N/m^2.
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A weight of 200 kg is suspended by vertical wire of length 600.5 cm The area of cross-section of wire is 1mm^2 when the load is removed the wire contracts by 0.5 cm the youngs modulus of material of wire wil be?
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A weight of 200 kg is suspended by vertical wire of length 600.5 cm The area of cross-section of wire is 1mm^2 when the load is removed the wire contracts by 0.5 cm the youngs modulus of material of wire wil be? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about A weight of 200 kg is suspended by vertical wire of length 600.5 cm The area of cross-section of wire is 1mm^2 when the load is removed the wire contracts by 0.5 cm the youngs modulus of material of wire wil be? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A weight of 200 kg is suspended by vertical wire of length 600.5 cm The area of cross-section of wire is 1mm^2 when the load is removed the wire contracts by 0.5 cm the youngs modulus of material of wire wil be?.
A weight of 200 kg is suspended by vertical wire of length 600.5 cm The area of cross-section of wire is 1mm^2 when the load is removed the wire contracts by 0.5 cm the youngs modulus of material of wire wil be? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about A weight of 200 kg is suspended by vertical wire of length 600.5 cm The area of cross-section of wire is 1mm^2 when the load is removed the wire contracts by 0.5 cm the youngs modulus of material of wire wil be? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A weight of 200 kg is suspended by vertical wire of length 600.5 cm The area of cross-section of wire is 1mm^2 when the load is removed the wire contracts by 0.5 cm the youngs modulus of material of wire wil be?.
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