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2 litres of SO2 gas at 760 mm Mercury are transferred to 10 l flask containing oxygen at the same temperature the partial pressure of SO2 in the flask is?
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2 litres of SO2 gas at 760 mm Mercury are transferred to 10 l flask co...
Introduction:
To calculate the partial pressure of SO2 gas in a flask containing oxygen, we need to consider the ideal gas law and Dalton's law of partial pressures.

Given information:
- Volume of SO2 gas = 2 litres
- Pressure of SO2 gas = 760 mm Hg
- Volume of flask = 10 litres
- Both gases are at the same temperature

Calculations:
1. Calculate the moles of SO2 gas using the ideal gas law:
n = PV/RT
n = (760 mm Hg * 2 L) / (0.0821 * T) (assuming T is constant)
2. Calculate the moles of oxygen gas in the flask:
n(O2) = PV/RT
n(O2) = (P * V) / (0.0821 * T)
3. Total moles of gas in the flask:
n(total) = n(SO2) + n(O2)
4. Calculate the partial pressure of SO2 gas using Dalton's law:
P(SO2) = X(SO2) * P(total)
where X(SO2) = n(SO2) / n(total)
P(total) = P(SO2) + P(O2)

Final answer:
By performing the above calculations, we can determine the partial pressure of SO2 gas in the flask containing oxygen at the given conditions.
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2 litres of SO2 gas at 760 mm Mercury are transferred to 10 l flask containing oxygen at the same temperature the partial pressure of SO2 in the flask is?
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