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Solve this equation.
The right limb of a single u tube manometer containing open atmosphere while the left limb is connected to the pie in which fluid of specific gravity 0.55 is flowing. The center of a pie 14cm below the level of mercury in right limb. Evaluate the pressure of fluid flowing in the pipe in difference of mercury level in the two limb is 22cm.?
The right limb of a single u tube manometer containing open atmosphere while the left limb is connected to the pie in which fluid of specific gravity 0.55 is flowing. The center of a pie 14cm below the level of mercury in right limb. Evaluate the pressure of fluid flowing in the pipe in difference of mercury level in the two limb is 22cm.?
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Solve this equation.The right limb of a single u tube manometer contai...
Understanding the Manometer Setup
In this problem, we are dealing with a U-tube manometer that measures the pressure of a fluid flowing in a pipe. The left limb of the manometer is connected to the pipe, while the right limb is open to the atmosphere.
Given Data
- Specific gravity of the fluid (SG) = 0.55
- Difference in mercury level (h) = 22 cm
- Depth of the pipe center below the mercury level in the right limb = 14 cm
Calculating the Pressure of the Fluid
1. Convert Specific Gravity to Density:
- The density of water (ρ_water) = 1000 kg/m³.
- Density of the fluid (ρ_fluid) = SG × ρ_water = 0.55 × 1000 = 550 kg/m³.
2. Calculate the Pressure Difference:
- The pressure difference due to the height difference in mercury (h_mercury) can be calculated using the formula:
Pressure difference (ΔP) = h_mercury × ρ_mercury × g
- The density of mercury (ρ_mercury) is approximately 13600 kg/m³.
- Thus, ΔP = 0.22 m (22 cm) × 13600 kg/m³ × 9.81 m/s².
3. Calculate the Pressure of the Fluid:
- The pressure at the center of the pipe can be expressed as:
P_pipe = ΔP + (h × ρ_fluid × g)
- Here, h = 0.14 m (14 cm) gives the additional pressure due to the depth of the pipe.
Final Calculation
To find the fluid pressure in the pipe, substitute values into the equations calculated above.
Conclusion
By following these calculations, you can evaluate the pressure of the fluid flowing in the pipe using the height difference observed in the manometer. This method provides an accurate way to measure hydraulic pressure using a simple U-tube manometer setup.
In this problem, we are dealing with a U-tube manometer that measures the pressure of a fluid flowing in a pipe. The left limb of the manometer is connected to the pipe, while the right limb is open to the atmosphere.
Given Data
- Specific gravity of the fluid (SG) = 0.55
- Difference in mercury level (h) = 22 cm
- Depth of the pipe center below the mercury level in the right limb = 14 cm
Calculating the Pressure of the Fluid
1. Convert Specific Gravity to Density:
- The density of water (ρ_water) = 1000 kg/m³.
- Density of the fluid (ρ_fluid) = SG × ρ_water = 0.55 × 1000 = 550 kg/m³.
2. Calculate the Pressure Difference:
- The pressure difference due to the height difference in mercury (h_mercury) can be calculated using the formula:
Pressure difference (ΔP) = h_mercury × ρ_mercury × g
- The density of mercury (ρ_mercury) is approximately 13600 kg/m³.
- Thus, ΔP = 0.22 m (22 cm) × 13600 kg/m³ × 9.81 m/s².
3. Calculate the Pressure of the Fluid:
- The pressure at the center of the pipe can be expressed as:
P_pipe = ΔP + (h × ρ_fluid × g)
- Here, h = 0.14 m (14 cm) gives the additional pressure due to the depth of the pipe.
Final Calculation
To find the fluid pressure in the pipe, substitute values into the equations calculated above.
Conclusion
By following these calculations, you can evaluate the pressure of the fluid flowing in the pipe using the height difference observed in the manometer. This method provides an accurate way to measure hydraulic pressure using a simple U-tube manometer setup.
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Solve this equation.The right limb of a single u tube manometer containing open atmosphere while the left limb is connected to the pie in which fluid of specific gravity 0.55 is flowing. The center of a pie 14cm below the level of mercury in right limb. Evaluate the pressure of fluid flowing in the pipe in difference of mercury level in the two limb is 22cm.?
Question Description
Solve this equation.The right limb of a single u tube manometer containing open atmosphere while the left limb is connected to the pie in which fluid of specific gravity 0.55 is flowing. The center of a pie 14cm below the level of mercury in right limb. Evaluate the pressure of fluid flowing in the pipe in difference of mercury level in the two limb is 22cm.? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about Solve this equation.The right limb of a single u tube manometer containing open atmosphere while the left limb is connected to the pie in which fluid of specific gravity 0.55 is flowing. The center of a pie 14cm below the level of mercury in right limb. Evaluate the pressure of fluid flowing in the pipe in difference of mercury level in the two limb is 22cm.? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Solve this equation.The right limb of a single u tube manometer containing open atmosphere while the left limb is connected to the pie in which fluid of specific gravity 0.55 is flowing. The center of a pie 14cm below the level of mercury in right limb. Evaluate the pressure of fluid flowing in the pipe in difference of mercury level in the two limb is 22cm.?.
Solve this equation.The right limb of a single u tube manometer containing open atmosphere while the left limb is connected to the pie in which fluid of specific gravity 0.55 is flowing. The center of a pie 14cm below the level of mercury in right limb. Evaluate the pressure of fluid flowing in the pipe in difference of mercury level in the two limb is 22cm.? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about Solve this equation.The right limb of a single u tube manometer containing open atmosphere while the left limb is connected to the pie in which fluid of specific gravity 0.55 is flowing. The center of a pie 14cm below the level of mercury in right limb. Evaluate the pressure of fluid flowing in the pipe in difference of mercury level in the two limb is 22cm.? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Solve this equation.The right limb of a single u tube manometer containing open atmosphere while the left limb is connected to the pie in which fluid of specific gravity 0.55 is flowing. The center of a pie 14cm below the level of mercury in right limb. Evaluate the pressure of fluid flowing in the pipe in difference of mercury level in the two limb is 22cm.?.
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Solve this equation.The right limb of a single u tube manometer containing open atmosphere while the left limb is connected to the pie in which fluid of specific gravity 0.55 is flowing. The center of a pie 14cm below the level of mercury in right limb. Evaluate the pressure of fluid flowing in the pipe in difference of mercury level in the two limb is 22cm.?, a detailed solution for Solve this equation.The right limb of a single u tube manometer containing open atmosphere while the left limb is connected to the pie in which fluid of specific gravity 0.55 is flowing. The center of a pie 14cm below the level of mercury in right limb. Evaluate the pressure of fluid flowing in the pipe in difference of mercury level in the two limb is 22cm.? has been provided alongside types of Solve this equation.The right limb of a single u tube manometer containing open atmosphere while the left limb is connected to the pie in which fluid of specific gravity 0.55 is flowing. The center of a pie 14cm below the level of mercury in right limb. Evaluate the pressure of fluid flowing in the pipe in difference of mercury level in the two limb is 22cm.? theory, EduRev gives you an
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