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Solve this equation.
A single column manometer is connected to a pipe containing a liquid of specific gravity 0.75. Find a pressure in the pipe, if the area of reservoir is 250 times the area of the tube for the manometer reading. The difference in mercury level is 40cm, on the left limb the fluid is up to the high of 20cm.?
A single column manometer is connected to a pipe containing a liquid of specific gravity 0.75. Find a pressure in the pipe, if the area of reservoir is 250 times the area of the tube for the manometer reading. The difference in mercury level is 40cm, on the left limb the fluid is up to the high of 20cm.?
Most Upvoted Answer
Solve this equation.A single column manometer is connected to a pipe c...
Understanding the Problem
To solve for the pressure in the pipe, we need to analyze the manometer setup. We have a liquid with a specific gravity of 0.75 and a mercury difference of 40 cm.
Given Data
- Specific gravity of the liquid (SG) = 0.75
- Difference in mercury level (hHg) = 40 cm
- Height of the fluid in the left limb (hLeft) = 20 cm
- Area ratio (A_reservoir/A_tube) = 250
Conversion and Calculation
1. Determine the density of the liquid:
- Density of water = 1000 kg/m³
- Density of the liquid = SG × Density of water = 0.75 × 1000 = 750 kg/m³
2. Calculate the pressure difference due to the mercury column:
- Density of mercury = 13600 kg/m³
- Pressure difference (ΔP) = hHg × Density of mercury × g (where g is the acceleration due to gravity, approximately 9.81 m/s²).
- ΔP = 0.40 m × 13600 kg/m³ × 9.81 m/s² = 53328 Pa (approximately).
3. Consider the height of the liquid in the left limb:
- The pressure at the left limb is due to the height of the liquid column.
- Pressure due to liquid = hLeft × Density of liquid × g = 0.20 m × 750 kg/m³ × 9.81 m/s² = 1471.5 Pa.
4. Calculate the pressure in the pipe:
- The pressure in the pipe (P_pipe) can be found by balancing the pressures.
- P_pipe = ΔP + Pressure due to liquid = 53328 Pa + 1471.5 Pa = 54800 Pa (approximately).
Final Result
The pressure in the pipe is approximately 54800 Pa.
To solve for the pressure in the pipe, we need to analyze the manometer setup. We have a liquid with a specific gravity of 0.75 and a mercury difference of 40 cm.
Given Data
- Specific gravity of the liquid (SG) = 0.75
- Difference in mercury level (hHg) = 40 cm
- Height of the fluid in the left limb (hLeft) = 20 cm
- Area ratio (A_reservoir/A_tube) = 250
Conversion and Calculation
1. Determine the density of the liquid:
- Density of water = 1000 kg/m³
- Density of the liquid = SG × Density of water = 0.75 × 1000 = 750 kg/m³
2. Calculate the pressure difference due to the mercury column:
- Density of mercury = 13600 kg/m³
- Pressure difference (ΔP) = hHg × Density of mercury × g (where g is the acceleration due to gravity, approximately 9.81 m/s²).
- ΔP = 0.40 m × 13600 kg/m³ × 9.81 m/s² = 53328 Pa (approximately).
3. Consider the height of the liquid in the left limb:
- The pressure at the left limb is due to the height of the liquid column.
- Pressure due to liquid = hLeft × Density of liquid × g = 0.20 m × 750 kg/m³ × 9.81 m/s² = 1471.5 Pa.
4. Calculate the pressure in the pipe:
- The pressure in the pipe (P_pipe) can be found by balancing the pressures.
- P_pipe = ΔP + Pressure due to liquid = 53328 Pa + 1471.5 Pa = 54800 Pa (approximately).
Final Result
The pressure in the pipe is approximately 54800 Pa.
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Solve this equation.A single column manometer is connected to a pipe containing a liquid of specific gravity 0.75. Find a pressure in the pipe, if the area of reservoir is 250 times the area of the tube for the manometer reading. The difference in mercury level is 40cm, on the left limb the fluid is up to the high of 20cm.?
Question Description
Solve this equation.A single column manometer is connected to a pipe containing a liquid of specific gravity 0.75. Find a pressure in the pipe, if the area of reservoir is 250 times the area of the tube for the manometer reading. The difference in mercury level is 40cm, on the left limb the fluid is up to the high of 20cm.? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about Solve this equation.A single column manometer is connected to a pipe containing a liquid of specific gravity 0.75. Find a pressure in the pipe, if the area of reservoir is 250 times the area of the tube for the manometer reading. The difference in mercury level is 40cm, on the left limb the fluid is up to the high of 20cm.? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Solve this equation.A single column manometer is connected to a pipe containing a liquid of specific gravity 0.75. Find a pressure in the pipe, if the area of reservoir is 250 times the area of the tube for the manometer reading. The difference in mercury level is 40cm, on the left limb the fluid is up to the high of 20cm.?.
Solve this equation.A single column manometer is connected to a pipe containing a liquid of specific gravity 0.75. Find a pressure in the pipe, if the area of reservoir is 250 times the area of the tube for the manometer reading. The difference in mercury level is 40cm, on the left limb the fluid is up to the high of 20cm.? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about Solve this equation.A single column manometer is connected to a pipe containing a liquid of specific gravity 0.75. Find a pressure in the pipe, if the area of reservoir is 250 times the area of the tube for the manometer reading. The difference in mercury level is 40cm, on the left limb the fluid is up to the high of 20cm.? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Solve this equation.A single column manometer is connected to a pipe containing a liquid of specific gravity 0.75. Find a pressure in the pipe, if the area of reservoir is 250 times the area of the tube for the manometer reading. The difference in mercury level is 40cm, on the left limb the fluid is up to the high of 20cm.?.
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