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Can you solve this equation.
The right limb of a single u tube manometer containing open atmosphere while the left limb is connected to the pie in which fluid of specific gravity 0.55 is flowing. The center of a pie 14cm below the level of mercury in right limb. Evaluate the pressure of fluid flowing in the pipe in difference of mercury level in the two limb is 22cm.?
The right limb of a single u tube manometer containing open atmosphere while the left limb is connected to the pie in which fluid of specific gravity 0.55 is flowing. The center of a pie 14cm below the level of mercury in right limb. Evaluate the pressure of fluid flowing in the pipe in difference of mercury level in the two limb is 22cm.?
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Can you solve this equation.The right limb of a single u tube manomete...
Understanding the Manometer Setup
In a single U-tube manometer, one limb is connected to a pipe carrying fluid, while the other limb is open to the atmosphere. The manometer measures the pressure difference between the fluid in the pipe and atmospheric pressure.
Given Data
- Specific gravity of fluid (SG) = 0.55
- Difference in mercury levels (h) = 22 cm
- Depth of the pipe center below mercury level = 14 cm
Calculating Pressure of the Fluid
1. Determine the Density of the Fluid:
- Density of mercury (ρ_mercury) = 13.6 g/cm³
- Density of the flowing fluid (ρ_fluid) = SG × ρ_mercury = 0.55 × 13.6 = 7.48 g/cm³
2. Calculate the Pressure Difference:
- The pressure difference (ΔP) caused by the height difference in mercury is given by:
ΔP = h × ρ_mercury × g
- Here, g is the acceleration due to gravity (which cancels out in calculations).
3. Convert Height to Pressure:
- ΔP = 22 cm × 13.6 g/cm³ = 299.2 g/cm²
4. Calculate the Pressure at the Pipe:
- The pressure at the fluid in the pipe (P_pipe) can be calculated by accounting for the depth:
- P_pipe = ΔP + (h_fluid × ρ_fluid × g)
- Where h_fluid is the height of the fluid column, which can be estimated from the center of the pipe depth.
5. Final Pressure Calculation:
- P_pipe = 299.2 g/cm² + (14 cm × 7.48 g/cm³) = 299.2 + 104.72 = 403.92 g/cm²
Conclusion
The pressure of the fluid flowing in the pipe is approximately 403.92 g/cm² or 4039.2 Pa when the pressure is measured in standard units.
In a single U-tube manometer, one limb is connected to a pipe carrying fluid, while the other limb is open to the atmosphere. The manometer measures the pressure difference between the fluid in the pipe and atmospheric pressure.
Given Data
- Specific gravity of fluid (SG) = 0.55
- Difference in mercury levels (h) = 22 cm
- Depth of the pipe center below mercury level = 14 cm
Calculating Pressure of the Fluid
1. Determine the Density of the Fluid:
- Density of mercury (ρ_mercury) = 13.6 g/cm³
- Density of the flowing fluid (ρ_fluid) = SG × ρ_mercury = 0.55 × 13.6 = 7.48 g/cm³
2. Calculate the Pressure Difference:
- The pressure difference (ΔP) caused by the height difference in mercury is given by:
ΔP = h × ρ_mercury × g
- Here, g is the acceleration due to gravity (which cancels out in calculations).
3. Convert Height to Pressure:
- ΔP = 22 cm × 13.6 g/cm³ = 299.2 g/cm²
4. Calculate the Pressure at the Pipe:
- The pressure at the fluid in the pipe (P_pipe) can be calculated by accounting for the depth:
- P_pipe = ΔP + (h_fluid × ρ_fluid × g)
- Where h_fluid is the height of the fluid column, which can be estimated from the center of the pipe depth.
5. Final Pressure Calculation:
- P_pipe = 299.2 g/cm² + (14 cm × 7.48 g/cm³) = 299.2 + 104.72 = 403.92 g/cm²
Conclusion
The pressure of the fluid flowing in the pipe is approximately 403.92 g/cm² or 4039.2 Pa when the pressure is measured in standard units.
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Can you solve this equation.The right limb of a single u tube manometer containing open atmosphere while the left limb is connected to the pie in which fluid of specific gravity 0.55 is flowing. The center of a pie 14cm below the level of mercury in right limb. Evaluate the pressure of fluid flowing in the pipe in difference of mercury level in the two limb is 22cm.?
Question Description
Can you solve this equation.The right limb of a single u tube manometer containing open atmosphere while the left limb is connected to the pie in which fluid of specific gravity 0.55 is flowing. The center of a pie 14cm below the level of mercury in right limb. Evaluate the pressure of fluid flowing in the pipe in difference of mercury level in the two limb is 22cm.? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about Can you solve this equation.The right limb of a single u tube manometer containing open atmosphere while the left limb is connected to the pie in which fluid of specific gravity 0.55 is flowing. The center of a pie 14cm below the level of mercury in right limb. Evaluate the pressure of fluid flowing in the pipe in difference of mercury level in the two limb is 22cm.? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Can you solve this equation.The right limb of a single u tube manometer containing open atmosphere while the left limb is connected to the pie in which fluid of specific gravity 0.55 is flowing. The center of a pie 14cm below the level of mercury in right limb. Evaluate the pressure of fluid flowing in the pipe in difference of mercury level in the two limb is 22cm.?.
Can you solve this equation.The right limb of a single u tube manometer containing open atmosphere while the left limb is connected to the pie in which fluid of specific gravity 0.55 is flowing. The center of a pie 14cm below the level of mercury in right limb. Evaluate the pressure of fluid flowing in the pipe in difference of mercury level in the two limb is 22cm.? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about Can you solve this equation.The right limb of a single u tube manometer containing open atmosphere while the left limb is connected to the pie in which fluid of specific gravity 0.55 is flowing. The center of a pie 14cm below the level of mercury in right limb. Evaluate the pressure of fluid flowing in the pipe in difference of mercury level in the two limb is 22cm.? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Can you solve this equation.The right limb of a single u tube manometer containing open atmosphere while the left limb is connected to the pie in which fluid of specific gravity 0.55 is flowing. The center of a pie 14cm below the level of mercury in right limb. Evaluate the pressure of fluid flowing in the pipe in difference of mercury level in the two limb is 22cm.?.
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