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Benzene and toluene form two ideal solution A and B at 313k. solution A(Total pressure Pa) contains equal mole of toluene and benzene. solution B contains equal masses of both (total pressure Pb).the vapour pressure of pure benzene and pure toluene are 160 and 60mmHg respectively at 313k. calculate the value of Pa/Pb?
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Benzene and toluene form two ideal solution A and B at 313k. solution ...
Given Data:
- Vapour pressure of pure benzene (P°benzene) = 160 mmHg
- Vapour pressure of pure toluene (P°toluene) = 60 mmHg
- Total pressure of solution A (Pa) = P°benzene + P°toluene
- Total pressure of solution B (Pb) = P°benzene + P°toluene
Calculation:
For solution A:
- Since solution A contains equal moles of benzene and toluene, the mole fraction of benzene (χbenzene) = 0.5 and the mole fraction of toluene (χtoluene) = 0.5
- Using Raoult's Law, the partial pressure of benzene in solution A (Pbenzene) = χbenzene * P°benzene = 0.5 * 160 = 80 mmHg
- Similarly, the partial pressure of toluene in solution A (Ptoluene) = χtoluene * P°toluene = 0.5 * 60 = 30 mmHg
- Therefore, the total pressure of solution A (Pa) = Pbenzene + Ptoluene = 80 + 30 = 110 mmHg
For solution B:
- Since solution B contains equal masses of benzene and toluene, the mole fraction of benzene and toluene will be different compared to solution A
- However, the total pressure of solution B (Pb) will remain the same as solution A, i.e., Pb = 110 mmHg
Calculation of Pa/Pb:
- Pa/Pb = 110/110 = 1
Conclusion:
The value of Pa/Pb is 1, indicating that the total pressures of both solutions A and B are equal at 313 K. This result is consistent with Raoult's Law and the ideal solution behavior.
- Vapour pressure of pure benzene (P°benzene) = 160 mmHg
- Vapour pressure of pure toluene (P°toluene) = 60 mmHg
- Total pressure of solution A (Pa) = P°benzene + P°toluene
- Total pressure of solution B (Pb) = P°benzene + P°toluene
Calculation:
For solution A:
- Since solution A contains equal moles of benzene and toluene, the mole fraction of benzene (χbenzene) = 0.5 and the mole fraction of toluene (χtoluene) = 0.5
- Using Raoult's Law, the partial pressure of benzene in solution A (Pbenzene) = χbenzene * P°benzene = 0.5 * 160 = 80 mmHg
- Similarly, the partial pressure of toluene in solution A (Ptoluene) = χtoluene * P°toluene = 0.5 * 60 = 30 mmHg
- Therefore, the total pressure of solution A (Pa) = Pbenzene + Ptoluene = 80 + 30 = 110 mmHg
For solution B:
- Since solution B contains equal masses of benzene and toluene, the mole fraction of benzene and toluene will be different compared to solution A
- However, the total pressure of solution B (Pb) will remain the same as solution A, i.e., Pb = 110 mmHg
Calculation of Pa/Pb:
- Pa/Pb = 110/110 = 1
Conclusion:
The value of Pa/Pb is 1, indicating that the total pressures of both solutions A and B are equal at 313 K. This result is consistent with Raoult's Law and the ideal solution behavior.
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Benzene and toluene form two ideal solution A and B at 313k. solution A(Total pressure Pa) contains equal mole of toluene and benzene. solution B contains equal masses of both (total pressure Pb).the vapour pressure of pure benzene and pure toluene are 160 and 60mmHg respectively at 313k. calculate the value of Pa/Pb?
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Benzene and toluene form two ideal solution A and B at 313k. solution A(Total pressure Pa) contains equal mole of toluene and benzene. solution B contains equal masses of both (total pressure Pb).the vapour pressure of pure benzene and pure toluene are 160 and 60mmHg respectively at 313k. calculate the value of Pa/Pb? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Benzene and toluene form two ideal solution A and B at 313k. solution A(Total pressure Pa) contains equal mole of toluene and benzene. solution B contains equal masses of both (total pressure Pb).the vapour pressure of pure benzene and pure toluene are 160 and 60mmHg respectively at 313k. calculate the value of Pa/Pb? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Benzene and toluene form two ideal solution A and B at 313k. solution A(Total pressure Pa) contains equal mole of toluene and benzene. solution B contains equal masses of both (total pressure Pb).the vapour pressure of pure benzene and pure toluene are 160 and 60mmHg respectively at 313k. calculate the value of Pa/Pb?.
Benzene and toluene form two ideal solution A and B at 313k. solution A(Total pressure Pa) contains equal mole of toluene and benzene. solution B contains equal masses of both (total pressure Pb).the vapour pressure of pure benzene and pure toluene are 160 and 60mmHg respectively at 313k. calculate the value of Pa/Pb? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Benzene and toluene form two ideal solution A and B at 313k. solution A(Total pressure Pa) contains equal mole of toluene and benzene. solution B contains equal masses of both (total pressure Pb).the vapour pressure of pure benzene and pure toluene are 160 and 60mmHg respectively at 313k. calculate the value of Pa/Pb? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Benzene and toluene form two ideal solution A and B at 313k. solution A(Total pressure Pa) contains equal mole of toluene and benzene. solution B contains equal masses of both (total pressure Pb).the vapour pressure of pure benzene and pure toluene are 160 and 60mmHg respectively at 313k. calculate the value of Pa/Pb?.
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Benzene and toluene form two ideal solution A and B at 313k. solution A(Total pressure Pa) contains equal mole of toluene and benzene. solution B contains equal masses of both (total pressure Pb).the vapour pressure of pure benzene and pure toluene are 160 and 60mmHg respectively at 313k. calculate the value of Pa/Pb?, a detailed solution for Benzene and toluene form two ideal solution A and B at 313k. solution A(Total pressure Pa) contains equal mole of toluene and benzene. solution B contains equal masses of both (total pressure Pb).the vapour pressure of pure benzene and pure toluene are 160 and 60mmHg respectively at 313k. calculate the value of Pa/Pb? has been provided alongside types of Benzene and toluene form two ideal solution A and B at 313k. solution A(Total pressure Pa) contains equal mole of toluene and benzene. solution B contains equal masses of both (total pressure Pb).the vapour pressure of pure benzene and pure toluene are 160 and 60mmHg respectively at 313k. calculate the value of Pa/Pb? theory, EduRev gives you an
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