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Is 7 times the 7th term of an ap is equal to 11 times 11th term then find its 18th term?
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Is 7 times the 7th term of an ap is equal to 11 times 11th term then f...
Given Information:
- 7 times the 7th term of an arithmetic progression (AP) is equal to 11 times the 11th term.

To Find:
- The 18th term of the arithmetic progression.

Solution:

Step 1: Understanding the Problem
- Let the first term of the AP be 'a' and the common difference be 'd'.
- The general form of the nth term of an AP is given by:
\[ T_n = a + (n-1)d \]

Step 2: Given Information
- According to the given information,
\[ 7(T_1 + 6d) = 11(T_1 + 10d) \]
\[ 7a + 42d = 11a + 110d \]
\[ 4a = 68d \]
\[ a = 17d \]

Step 3: Calculating the 18th Term
- We need to find the 18th term of the AP using the formula:
\[ T_{18} = a + 17d \]
\[ T_{18} = 17d + 17(17d) \]
\[ T_{18} = 17d + 289d \]
\[ T_{18} = 306d \]

Step 4: Final Answer
- Therefore, the 18th term of the arithmetic progression is 306d.
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