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10 ml of a solution of NaOH is found to be completely neutralised by 8mL of a given solution of HCl. If we take 20 mL of the same solution of NaOH, the amount HCl solution (the same solution as before) required to neutralise it will be–
  • a)
    4 mL
  • b)
    8 mL
  • c)
    12 mL
  • d)
    16 mL
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
10 ml of a solution of NaOH is found to be completely neutralised by 8...
Since 10 mL of NaOH solution requires 8 mL of HCl solution
Therefore, 20 mL of NaOH solution will require 8 * 2 = 16 mL of HCl solution
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Most Upvoted Answer
10 ml of a solution of NaOH is found to be completely neutralised by 8...
In first case the amount of NaOH is 10ml and the amount of HCl is 8ml.In the second case the amount of NaOH is 20ml twice the amount in first case so the HCl be also twice that is 16ml.
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Community Answer
10 ml of a solution of NaOH is found to be completely neutralised by 8...
According to the given information, 10 mL of NaOH solution is completely neutralized by 8 mL of HCl solution.

Therefore, the ratio of NaOH to HCl in the neutralization reaction is 10:8, or simplified, 5:4.

If we take 20 mL of the same NaOH solution, we can use the same ratio to find the amount of HCl solution required to neutralize it.

Using the ratio 5:4, we can set up a proportion:

10 mL / 8 mL = 20 mL / x

Solving for x:
10x = 8 * 20
10x = 160
x = 16

Therefore, 16 mL of the same HCl solution will be required to neutralize 20 mL of the NaOH solution.
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10 ml of a solution of NaOH is found to be completely neutralised by 8mL of a given solution of HCl.If we take 20 mL of the same solution of NaOH, the amount HCl solution (the same solution as before)required to neutralise it will be–a)4 mLb)8 mLc)12 mLd)16 mLCorrect answer is option 'D'. Can you explain this answer?
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