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If the point p( x,y) is situated on a circle whose centre is (3,-2) and whose radius is 3 . then probe that x square + y square- 6x + 4y+ 4= 0?
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If the point p( x,y) is situated on a circle whose centre is (3,-2) an...
Given Information:
- Center of the circle: (3, -2)
- Radius of the circle: 3
- Point on the circle: P(x, y)

Derivation:
- The general equation of a circle is given by: (x - h)^2 + (y - k)^2 = r^2, where (h, k) is the center of the circle and r is the radius.
- Substituting the given values, we get: (x - 3)^2 + (y + 2)^2 = 3^2
- Expanding and simplifying, we get: x^2 - 6x + 9 + y^2 + 4y + 4 = 9
- Rearranging terms, we get: x^2 + y^2 - 6x + 4y + 4 = 0

Conclusion:
- Therefore, the equation x^2 + y^2 - 6x + 4y + 4 = 0 represents a circle with center (3, -2) and radius 3, and the point P(x, y) lies on this circle.
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If the point p( x,y) is situated on a circle whose centre is (3,-2) and whose radius is 3 . then probe that x square + y square- 6x + 4y+ 4= 0?
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