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0.01 mole of a non electrolyte is dissolved in 10 grams of water the molality of the solution is?
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0.01 mole of a non electrolyte is dissolved in 10 grams of water the m...
Calculation of Molality of the Solution
• The molality (m) of a solution is defined as the number of moles of solute per kilogram of solvent.
• Given that 0.01 mole of a non-electrolyte is dissolved in 10 grams of water.
• First, we need to convert the mass of water from grams to kilograms.
• The molar mass of water is 18 g/mol. Therefore, 10 grams of water is equal to 10/18 = 0.5556 moles.
• This corresponds to 0.5556 kg of water.
• Now, we can calculate the molality of the solution using the formula:
Molality (m) = moles of solute / kg of solvent
Molality (m) = 0.01 moles / 0.5556 kg
Molality (m) ≈ 0.018 mol/kg

Conclusion
• The molality of the solution is approximately 0.018 mol/kg.
• This means that there are 0.018 moles of the non-electrolyte dissolved in every kilogram of water in the solution.
• Molality is a useful measure of concentration, especially in situations where the temperature of the solution might change.
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0.01 mole of a non electrolyte is dissolved in 10 grams of water the molality of the solution is?
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