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Two resistors of resistance 100 ohms and 400 ohms are connected in series to a battery of EMF 100 volt along with a plug key draw a circuit diagram for it?
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Two resistors of resistance 100 ohms and 400 ohms are connected in ser...
Circuit Diagram and Explanation:

Circuit Diagram:
- Battery (EMF 100V) ----(100 ohm resistor)----(400 ohm resistor)---- Plug key

Explanation:
- The circuit consists of a battery with an electromotive force (EMF) of 100 volts connected to two resistors in series.
- The first resistor has a resistance of 100 ohms, and the second resistor has a resistance of 400 ohms.
- The plug key is used to open or close the circuit, allowing the current to flow through the resistors.
- When the circuit is closed, the current flows from the positive terminal of the battery, through the 100-ohm resistor, then through the 400-ohm resistor, and back to the negative terminal of the battery.
- The total resistance in a series circuit is the sum of the individual resistances, so in this case, the total resistance is 100 ohms + 400 ohms = 500 ohms.
- Using Ohm's Law (V = IR), we can calculate the current flowing through the circuit by dividing the voltage (100V) by the total resistance (500 ohms), giving us a current of 0.2 amperes.
- The potential difference across each resistor can be calculated using Ohm's Law, where V = IR. So, the potential difference across the 100-ohm resistor is 20 volts (0.2 A * 100 ohms) and across the 400-ohm resistor is 80 volts (0.2 A * 400 ohms).
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Two resistors of resistance 100 ohms and 400 ohms are connected in series to a battery of EMF 100 volt along with a plug key draw a circuit diagram for it?
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