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Gravel is dropped into a conveyor belt at a rate of 0.5 kg/second the extra force required to keep the belt moving at 10 meter/second is?
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Gravel is dropped into a conveyor belt at a rate of 0.5 kg/second the ...
Calculating the Extra Force Required to Keep the Conveyor Belt Moving:
The extra force required to keep the conveyor belt moving at a constant speed can be calculated using the equation:
\[ F_{\text{extra}} = \frac{d(mv)}{dt} \]
Where:
- \( F_{\text{extra}} \) = Extra force required (N)
- \( m \) = Mass of the gravel on the conveyor belt (kg)
- \( v \) = Velocity of the conveyor belt (m/s)
- \( t \) = Time

Given Data:
- Mass flow rate of gravel (\( \frac{dm}{dt} \)) = 0.5 kg/s
- Velocity of the conveyor belt (\( v \)) = 10 m/s

Calculating the Mass of Gravel on the Conveyor Belt:
The mass of the gravel on the conveyor belt at any given time can be calculated using the equation:
\[ m = \text{Mass flow rate} \times t \]
Substitute the given values:
\[ m = 0.5 \times t \]

Substitute the Mass Equation into the Force Equation:
\[ F_{\text{extra}} = \frac{d(0.5t \times 10)}{dt} \]
\[ F_{\text{extra}} = \frac{5}{2} \]
Therefore, the extra force required to keep the conveyor belt moving at 10 m/s is 2.5 N.
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Gravel is dropped into a conveyor belt at a rate of 0.5 kg/second the extra force required to keep the belt moving at 10 meter/second is?
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