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Gravel is drop them token where @ 0.5 kg per second the extra force required in Newton to keep the belt moving at 10 M per second is?
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Gravel is drop them token where @ 0.5 kg per second the extra force re...
Extra Force Required to Keep the Belt Moving
In order to calculate the extra force required to keep the belt moving at 10 m/s while gravel is being dropped onto it, we need to consider the rate at which gravel is being dropped and the velocity of the belt.

Given Data:
- Rate of gravel drop: 0.5 kg/s
- Velocity of belt: 10 m/s

Formula:
The extra force required can be calculated using the formula:
\[ F = \frac{dp}{dt} \times v \]
Where:
- \( F \) = Extra force required (in Newton)
- \( \frac{dp}{dt} \) = Rate of change of momentum (in kg/s)
- \( v \) = Velocity of the belt (in m/s)

Calculation:
- Rate of change of momentum (\( \frac{dp}{dt} \)) = 0.5 kg/s
- Velocity of the belt (\( v \)) = 10 m/s
Substitute the values into the formula:
\[ F = 0.5 \times 10 = 5 \, N \]
Therefore, the extra force required to keep the belt moving at 10 m/s while gravel is being dropped at 0.5 kg/s is 5 Newtons.
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Gravel is drop them token where @ 0.5 kg per second the extra force required in Newton to keep the belt moving at 10 M per second is?
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