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A mass of object is 800 kg moving with velocity 54 km/ hrs collide with stable identical mass . if collision is perfectly inelastic than find :
a) velocity of particles after collision
b) kinetic energy of system after collision
c) loss of kinetic energy?
a) velocity of particles after collision
b) kinetic energy of system after collision
c) loss of kinetic energy?
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A mass of object is 800 kg moving with velocity 54 km/ hrs collide wit...
Given data:
- Mass of object 1 (m1) = 800 kg
- Velocity of object 1 (v1) = 54 km/hr
- Mass of object 2 (m2) = 800 kg (identical to object 1)
- Velocity of object 2 (v2) = 0 km/hr (stable)
a) Velocity of particles after collision:
In a perfectly inelastic collision, the two objects stick together after the collision. The velocity of the combined mass can be calculated using the principle of conservation of momentum.
Total initial momentum = Total final momentum
(m1 * v1) + (m2 * v2) = (m1 + m2) * vf
(800 kg * 54 km/hr) + (800 kg * 0 km/hr) = (800 kg + 800 kg) * vf
43200 kg*km/hr = 1600 kg * vf
vf = 27 km/hr
b) Kinetic energy of system after collision:
The kinetic energy of the system after the collision can be calculated using the formula:
KE = 0.5 * (m1 + m2) * vf^2
KE = 0.5 * 1600 kg * (27 km/hr)^2
KE = 0.5 * 1600 kg * 729 km^2/hr^2
KE = 584400 J
c) Loss of kinetic energy:
The loss of kinetic energy can be calculated by finding the difference between the initial kinetic energy and the final kinetic energy of the system.
Initial kinetic energy = 0.5 * m1 * v1^2
Initial kinetic energy = 0.5 * 800 kg * (54 km/hr)^2
Initial kinetic energy = 0.5 * 800 kg * 2916 km^2/hr^2
Initial kinetic energy = 1166400 J
Loss of kinetic energy = Initial KE - Final KE
Loss of kinetic energy = 1166400 J - 584400 J
Loss of kinetic energy = 582000 J
Therefore, after the perfectly inelastic collision, the velocity of the combined mass is 27 km/hr, the kinetic energy of the system is 584400 J, and the loss of kinetic energy is 582000 J.
- Mass of object 1 (m1) = 800 kg
- Velocity of object 1 (v1) = 54 km/hr
- Mass of object 2 (m2) = 800 kg (identical to object 1)
- Velocity of object 2 (v2) = 0 km/hr (stable)
a) Velocity of particles after collision:
In a perfectly inelastic collision, the two objects stick together after the collision. The velocity of the combined mass can be calculated using the principle of conservation of momentum.
Total initial momentum = Total final momentum
(m1 * v1) + (m2 * v2) = (m1 + m2) * vf
(800 kg * 54 km/hr) + (800 kg * 0 km/hr) = (800 kg + 800 kg) * vf
43200 kg*km/hr = 1600 kg * vf
vf = 27 km/hr
b) Kinetic energy of system after collision:
The kinetic energy of the system after the collision can be calculated using the formula:
KE = 0.5 * (m1 + m2) * vf^2
KE = 0.5 * 1600 kg * (27 km/hr)^2
KE = 0.5 * 1600 kg * 729 km^2/hr^2
KE = 584400 J
c) Loss of kinetic energy:
The loss of kinetic energy can be calculated by finding the difference between the initial kinetic energy and the final kinetic energy of the system.
Initial kinetic energy = 0.5 * m1 * v1^2
Initial kinetic energy = 0.5 * 800 kg * (54 km/hr)^2
Initial kinetic energy = 0.5 * 800 kg * 2916 km^2/hr^2
Initial kinetic energy = 1166400 J
Loss of kinetic energy = Initial KE - Final KE
Loss of kinetic energy = 1166400 J - 584400 J
Loss of kinetic energy = 582000 J
Therefore, after the perfectly inelastic collision, the velocity of the combined mass is 27 km/hr, the kinetic energy of the system is 584400 J, and the loss of kinetic energy is 582000 J.
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A mass of object is 800 kg moving with velocity 54 km/ hrs collide with stable identical mass . if collision is perfectly inelastic than find : a) velocity of particles after collision b) kinetic energy of system after collision c) loss of kinetic energy?
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A mass of object is 800 kg moving with velocity 54 km/ hrs collide with stable identical mass . if collision is perfectly inelastic than find : a) velocity of particles after collision b) kinetic energy of system after collision c) loss of kinetic energy? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A mass of object is 800 kg moving with velocity 54 km/ hrs collide with stable identical mass . if collision is perfectly inelastic than find : a) velocity of particles after collision b) kinetic energy of system after collision c) loss of kinetic energy? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A mass of object is 800 kg moving with velocity 54 km/ hrs collide with stable identical mass . if collision is perfectly inelastic than find : a) velocity of particles after collision b) kinetic energy of system after collision c) loss of kinetic energy?.
A mass of object is 800 kg moving with velocity 54 km/ hrs collide with stable identical mass . if collision is perfectly inelastic than find : a) velocity of particles after collision b) kinetic energy of system after collision c) loss of kinetic energy? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A mass of object is 800 kg moving with velocity 54 km/ hrs collide with stable identical mass . if collision is perfectly inelastic than find : a) velocity of particles after collision b) kinetic energy of system after collision c) loss of kinetic energy? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A mass of object is 800 kg moving with velocity 54 km/ hrs collide with stable identical mass . if collision is perfectly inelastic than find : a) velocity of particles after collision b) kinetic energy of system after collision c) loss of kinetic energy?.
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