Ratio of Distance Transverse in Successive Intervals of Time for a Falling Body
The ratio of distance transversed in successive intervals of time by a body falling from rest can be explained using the concept of acceleration due to gravity.

Explanation
- When an object falls from rest, it accelerates due to the force of gravity acting on it.
- The acceleration due to gravity is a constant value, denoted by 'g' and is approximately equal to 9.81 m/s^2 on the surface of the Earth.
- As the object falls, its velocity increases continuously, leading to the distance transversed increasing in each successive interval of time.
- The distance transversed in each interval of time is directly proportional to the square of the time interval.
- Mathematically, the ratio of distance transversed in successive intervals of time can be represented as (d2/d1) = (t2^2/t1^2), where d1 and d2 are the distances transversed in time intervals t1 and t2 respectively.
- This ratio shows that the distance transversed increases quadratically with time, highlighting the acceleration of the falling object.
- Therefore, the ratio of distance transversed in successive intervals of time by a body falling from rest follows a quadratic relationship with time due to the constant acceleration of gravity.