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200ml of a gas st 27°C and 1140 mm pressure is transferred to a vessel of 450ml capacity. What temperature is to be applied if the pressure applied is 1 atmosphere?
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200ml of a gas st 27°C and 1140 mm pressure is transferred to a vessel...
Calculating the Temperature of the Gas:
1. Initial Conditions:
- Volume of gas (V1) = 200 ml = 0.2 L
- Temperature (T1) = 27°C = 27 + 273 = 300 K
- Pressure (P1) = 1140 mm Hg = 1140/760 atm = 1.5 atm
2. Final Conditions:
- Volume of vessel (V2) = 450 ml = 0.45 L
- Pressure (P2) = 1 atm
3. Using the Combined Gas Law equation:
- (P1 * V1) / T1 = (P2 * V2) / T2
4. Plugging in the values:
- (1.5 * 0.2) / 300 = (1 * 0.45) / T2
- 0.3 / 300 = 0.45 / T2
- T2 = (0.45 * 300) / 0.3
- T2 = 450 K
5. Converting back to Celsius:
- Temperature (T2) = 450 K - 273 = 177°C
Therefore, the temperature to be applied to the gas in order to achieve a pressure of 1 atmosphere in a vessel of 450ml capacity is 177°C.
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200ml of a gas st 27°C and 1140 mm pressure is transferred to a vessel...
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200ml of a gas st 27°C and 1140 mm pressure is transferred to a vessel of 450ml capacity. What temperature is to be applied if the pressure applied is 1 atmosphere?
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