A circular shaft of 60mm diameter is running at 150rpm. If the shear s...
Given Data- Diameter of the shaft, d = 60 mm = 0.06 m
- Radius, r = d/2 = 0.03 m
- Speed, N = 150 rpm
- Maximum shear stress, τ = 50 MPa = 50 × 10
6 Pa
Calculate Polar Moment of InertiaThe polar moment of inertia (J) for a circular shaft is given by:
J = (π/32) × d4
Substituting the value of d:
J = (π/32) × (0.06)4 = 1.13097 × 10-9 m4
Calculate Maximum Torque (T)The maximum torque (T) can be calculated using the formula:
T = τ × J / r
Substituting the known values:
T = (50 × 106) × (1.13097 × 10-9) / 0.03
Calculating T:
T = 188.49 Nm
Calculate Power Transmitted (P)Power (P) transmitted by the shaft is given by:
P = (2πNT) / 60
Substituting N and T:
P = (2π × 150 × 188.49) / 60
Calculating P:
P ≈ 59.06 kW
ConclusionThe power which can be transmitted by the shaft, with a maximum shear stress of 50 MPa, is approximately **59.06 kW**.