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The force experienced by a pole of strength 100 Am at a
listance of 0.2 m from a short magnet of length 5 cm and
pole strength of 200 Am on its axial line will be?
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The force experienced by a pole of strength 100 Am at alistance of 0.2...
Introduction
To calculate the force experienced by a pole due to a magnet, we can use the formula for the force between two magnetic poles. The formula is given by:

F = (μ₀/4π) * (p₁ * p₂) / r²
where:
- F is the force between the poles,
- μ₀ is the permeability of free space (4π × 10⁻⁷ T m/A),
- p₁ and p₂ are the pole strengths,
- r is the distance between the poles.

Given Data
- Pole strength of the first pole, p₁ = 100 Am
- Pole strength of the magnet, p₂ = 200 Am
- Distance from the magnet, r = 0.2 m
- Length of the magnet is not directly needed for this calculation.

Substituting Values
Using the formula, we can substitute the values:
- μ₀ = 4π × 10⁻⁷ T m/A
- p₁ = 100 Am
- p₂ = 200 Am
- r = 0.2 m
The force can be calculated as follows:

F = (4π × 10⁻⁷ / 4π) * (100 * 200) / (0.2)²
This simplifies to:

F = (10⁻⁷) * (20000) / 0.04

F = (10⁻⁷) * (500000)

F = 5 × 10⁻² N

Conclusion
The force experienced by the pole at a distance of 0.2 m from the short magnet is:

F = 0.05 N
This force acts along the axial line between the two poles, drawing them closer together.
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The force experienced by a pole of strength 100 Am at alistance of 0.2 m from a short magnet of length 5 cm andpole strength of 200 Am on its axial line will be?
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