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When a 10-ampere current is passed through acidulated water (H₂O containing some H2SO4), 2.24 litres H₂ gas is evolved at NTP. The duration for which current is passed through acidulated water is:?
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When a 10-ampere current is passed through acidulated water (H₂O conta...
Understanding the Problem
To determine the duration for which a 10-ampere current is passed through acidulated water, we need to utilize Faraday's laws of electrolysis and the molar volume of gases at Normal Temperature and Pressure (NTP).
Key Concepts
- **Faraday's Law of Electrolysis**: One mole of gas is evolved at an electrode for every 96500 coulombs of charge passed through the electrolyte.
- **Molar Volume at NTP**: At NTP, one mole of any gas occupies 22.4 liters.
Calculating Moles of Hydrogen Gas
- **Volume of H₂ Gas**: Given that 2.24 liters of H₂ gas is evolved, we calculate the moles of H₂:
\[
\text{Moles of H₂} = \frac{\text{Volume at NTP}}{\text{Molar Volume}} = \frac{2.24 \, \text{liters}}{22.4 \, \text{liters/mole}} = 0.1 \, \text{moles}
\]
Charge Required for Electrolysis
- **Charge (Q) Calculation**: Using Faraday's law, the charge required to produce 0.1 moles of H₂ is:
\[
Q = \text{Moles} \times 96500 \, \text{Coulombs/mole} = 0.1 \times 96500 = 9650 \, \text{Coulombs}
\]
Time Calculation
- **Using Current (I)**: The relationship between charge, current, and time is given by:
\[
Q = I \times t \implies t = \frac{Q}{I}
\]
Substituting the values:
\[
t = \frac{9650}{10} = 965 \, \text{seconds} \approx 16.08 \, \text{minutes}
\]
Conclusion
Thus, the duration for which the current was passed through the acidulated water is approximately **16.08 minutes**.
To determine the duration for which a 10-ampere current is passed through acidulated water, we need to utilize Faraday's laws of electrolysis and the molar volume of gases at Normal Temperature and Pressure (NTP).
Key Concepts
- **Faraday's Law of Electrolysis**: One mole of gas is evolved at an electrode for every 96500 coulombs of charge passed through the electrolyte.
- **Molar Volume at NTP**: At NTP, one mole of any gas occupies 22.4 liters.
Calculating Moles of Hydrogen Gas
- **Volume of H₂ Gas**: Given that 2.24 liters of H₂ gas is evolved, we calculate the moles of H₂:
\[
\text{Moles of H₂} = \frac{\text{Volume at NTP}}{\text{Molar Volume}} = \frac{2.24 \, \text{liters}}{22.4 \, \text{liters/mole}} = 0.1 \, \text{moles}
\]
Charge Required for Electrolysis
- **Charge (Q) Calculation**: Using Faraday's law, the charge required to produce 0.1 moles of H₂ is:
\[
Q = \text{Moles} \times 96500 \, \text{Coulombs/mole} = 0.1 \times 96500 = 9650 \, \text{Coulombs}
\]
Time Calculation
- **Using Current (I)**: The relationship between charge, current, and time is given by:
\[
Q = I \times t \implies t = \frac{Q}{I}
\]
Substituting the values:
\[
t = \frac{9650}{10} = 965 \, \text{seconds} \approx 16.08 \, \text{minutes}
\]
Conclusion
Thus, the duration for which the current was passed through the acidulated water is approximately **16.08 minutes**.
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When a 10-ampere current is passed through acidulated water (H₂O containing some H2SO4), 2.24 litres H₂ gas is evolved at NTP. The duration for which current is passed through acidulated water is:?
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When a 10-ampere current is passed through acidulated water (H₂O containing some H2SO4), 2.24 litres H₂ gas is evolved at NTP. The duration for which current is passed through acidulated water is:? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about When a 10-ampere current is passed through acidulated water (H₂O containing some H2SO4), 2.24 litres H₂ gas is evolved at NTP. The duration for which current is passed through acidulated water is:? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for When a 10-ampere current is passed through acidulated water (H₂O containing some H2SO4), 2.24 litres H₂ gas is evolved at NTP. The duration for which current is passed through acidulated water is:?.
When a 10-ampere current is passed through acidulated water (H₂O containing some H2SO4), 2.24 litres H₂ gas is evolved at NTP. The duration for which current is passed through acidulated water is:? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about When a 10-ampere current is passed through acidulated water (H₂O containing some H2SO4), 2.24 litres H₂ gas is evolved at NTP. The duration for which current is passed through acidulated water is:? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for When a 10-ampere current is passed through acidulated water (H₂O containing some H2SO4), 2.24 litres H₂ gas is evolved at NTP. The duration for which current is passed through acidulated water is:?.
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