How do cleavage cause size of the cell to be reduced explain with the ...
Cleavage and Cell Size Reduction
Cleavage is a crucial process during early embryonic development, characterized by rapid cell division without significant growth. This leads to a reduction in cell size.
Process of Cleavage
- Cleavage occurs after fertilization and involves multiple mitotic divisions of the zygote.
- These divisions are termed cleavage divisions and typically occur in a synchronized manner.
Reduction in Cell Size
- During cleavage, the volume of the zygote remains relatively constant.
- Each cleavage division divides the existing cytoplasm into smaller cells (blastomeres).
Mechanism Explained
- **Cell Division**: Cleavage divides the zygote into smaller cells, but the overall cytoplasmic volume does not increase significantly.
- **Cell Cycle**: The cell cycle during cleavage is rapid, with a shorter G1 phase and minimal growth, leading to decreased cell size.
- **Cytoplasmic Partitioning**: As the zygote divides, the cytoplasm is partitioned into smaller segments, resulting in smaller cells.
Diagrammatic Representation
[Zygote] --> [2-cell stage] --> [4-cell stage] --> [8-cell stage]
- Each stage represents the division, exhibiting a decrease in the size of each individual cell while maintaining the overall volume of the zygote.
Conclusion
- The process of cleavage ensures that the resulting cells are smaller, allowing for efficient cellular development and eventual differentiation.
- This reduction in size is essential for the subsequent stages of embryonic development, enabling the formation of complex structures.
In summary, cleavage results in smaller cell sizes through rapid divisions and minimal growth, ensuring a compact and organized cellular environment for early development.
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