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The capacity of a condenser 'A' is 10 μF and it is charged by a battery of 100V. The battery is disconnected and the condenser is connected to a condenser 'B'. The common potential is 40V. The capacity of 'B' is
- a)8 μF
- b)15 μF
- c)2 μF
- d)1 μF
Correct answer is option 'B'. Can you explain this answer?
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Most Upvoted Answer
The capacity of a condenser A is 10 μF and it is charged by a batte...
Understanding the Problem
When a charged condenser (capacitor) is connected to another uncharged condenser, the total charge and voltage change. Here, we start with condenser A charged to 100V and then connect it to condenser B after disconnecting the battery.
Given Data
- Capacity of condenser A (C₁) = 10 μF
- Voltage of battery (V₁) = 100V
- Common potential after connection (Vf) = 40V
Charging of Condensers
1. Initial Charge of A:
\[
Q₁ = C₁ \cdot V₁ = 10 \, \mu F \cdot 100 \, V = 1000 \, \mu C
\]
2. Final Charge Distribution:
- After connecting to condenser B, both capacitors A and B will have the same final voltage (Vf).
- The total charge remains conserved:
\[
Q₁ = Qf + Q₂
\]
where \(Qf\) is the charge on A and \(Q₂\) is the charge on B.
3. Charge on Capacitors:
\[
Qf = C₁ \cdot Vf = 10 \, \mu F \cdot 40 \, V = 400 \, \mu C
\]
\[
Q₂ = Q₁ - Qf = 1000 \, \mu C - 400 \, \mu C = 600 \, \mu C
\]
4. Finding Capacity of B:
Using the charge on B and the final voltage:
\[
Q₂ = C₂ \cdot Vf \Rightarrow C₂ = \frac{Q₂}{Vf} = \frac{600 \, \mu C}{40 \, V} = 15 \, \mu F
\]
Conclusion
Therefore, the capacity of condenser B is 15 μF, confirming that option b is correct.
When a charged condenser (capacitor) is connected to another uncharged condenser, the total charge and voltage change. Here, we start with condenser A charged to 100V and then connect it to condenser B after disconnecting the battery.
Given Data
- Capacity of condenser A (C₁) = 10 μF
- Voltage of battery (V₁) = 100V
- Common potential after connection (Vf) = 40V
Charging of Condensers
1. Initial Charge of A:
\[
Q₁ = C₁ \cdot V₁ = 10 \, \mu F \cdot 100 \, V = 1000 \, \mu C
\]
2. Final Charge Distribution:
- After connecting to condenser B, both capacitors A and B will have the same final voltage (Vf).
- The total charge remains conserved:
\[
Q₁ = Qf + Q₂
\]
where \(Qf\) is the charge on A and \(Q₂\) is the charge on B.
3. Charge on Capacitors:
\[
Qf = C₁ \cdot Vf = 10 \, \mu F \cdot 40 \, V = 400 \, \mu C
\]
\[
Q₂ = Q₁ - Qf = 1000 \, \mu C - 400 \, \mu C = 600 \, \mu C
\]
4. Finding Capacity of B:
Using the charge on B and the final voltage:
\[
Q₂ = C₂ \cdot Vf \Rightarrow C₂ = \frac{Q₂}{Vf} = \frac{600 \, \mu C}{40 \, V} = 15 \, \mu F
\]
Conclusion
Therefore, the capacity of condenser B is 15 μF, confirming that option b is correct.
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The capacity of a condenser A is 10 μF and it is charged by a battery of 100V. The battery is disconnected and the condenser is connected to a condenser B. The common potential is 40V. The capacity of B isa)8 μFb)15 μFc)2 μFd)1 μFCorrect answer is option 'B'. Can you explain this answer?
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The capacity of a condenser A is 10 μF and it is charged by a battery of 100V. The battery is disconnected and the condenser is connected to a condenser B. The common potential is 40V. The capacity of B isa)8 μFb)15 μFc)2 μFd)1 μFCorrect answer is option 'B'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about The capacity of a condenser A is 10 μF and it is charged by a battery of 100V. The battery is disconnected and the condenser is connected to a condenser B. The common potential is 40V. The capacity of B isa)8 μFb)15 μFc)2 μFd)1 μFCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The capacity of a condenser A is 10 μF and it is charged by a battery of 100V. The battery is disconnected and the condenser is connected to a condenser B. The common potential is 40V. The capacity of B isa)8 μFb)15 μFc)2 μFd)1 μFCorrect answer is option 'B'. Can you explain this answer?.
The capacity of a condenser A is 10 μF and it is charged by a battery of 100V. The battery is disconnected and the condenser is connected to a condenser B. The common potential is 40V. The capacity of B isa)8 μFb)15 μFc)2 μFd)1 μFCorrect answer is option 'B'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about The capacity of a condenser A is 10 μF and it is charged by a battery of 100V. The battery is disconnected and the condenser is connected to a condenser B. The common potential is 40V. The capacity of B isa)8 μFb)15 μFc)2 μFd)1 μFCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The capacity of a condenser A is 10 μF and it is charged by a battery of 100V. The battery is disconnected and the condenser is connected to a condenser B. The common potential is 40V. The capacity of B isa)8 μFb)15 μFc)2 μFd)1 μFCorrect answer is option 'B'. Can you explain this answer?.
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