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The equivalent weight of metal in different compounds are 18.6 and 28 Atomic mass of the metal would be
1) 18.6
2) 28
3) 46.6
4) 56?
Most Upvoted Answer
The equivalent weight of metal in different compounds are 18.6 and 28 ...
Understanding Equivalent Weight
Equivalent weight of a metal can be defined as the mass of the metal that combines with or displaces 1 mole of hydrogen (or 8 grams of oxygen). The equivalent weight can be calculated using the formula:
Equivalent Weight = Atomic Mass / n
where 'n' is the valency of the metal.
Given Data
- Equivalent weights of the metal in two compounds:
- Compound 1: 18.6
- Compound 2: 28
Calculating Atomic Mass
To find the atomic mass of the metal, we need to determine 'n' for both compounds.
- For the first compound:
- Let n1 be the valency for the first compound.
- Hence, Atomic Mass = 18.6 * n1
- For the second compound:
- Let n2 be the valency for the second compound.
- Hence, Atomic Mass = 28 * n2
Equating the Atomic Mass
Since both expressions represent the atomic mass of the same metal, we can set them equal to each other:
18.6 * n1 = 28 * n2
From the above equation, we can explore possible integer values for n1 and n2 that make the equation valid.
Finding Possible Values
- If we assume n1 = 2 (common for metals), then:
- Atomic Mass = 18.6 * 2 = 37.2
- If n2 = 1, then:
- Atomic Mass = 28 * 1 = 28
This does not give a consistent value.
- Testing n1 = 1, n2 = 1:
- Atomic Mass = 18.6 * 1 = 18.6
- Atomic Mass = 28 * 1 = 28
Both do not yield an integer solution.
Testing Other Values
Through trial with other integers, we find that:
- n1 = 3 and n2 = 2 leads to:
- Atomic Mass = 18.6 * 3 = 55.8 (close to 56)
- Atomic Mass = 28 * 2 = 56
Conclusion
Thus, the atomic mass of the metal is approximately 56, making option 4) 56 the correct answer.
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The equivalent weight of metal in different compounds are 18.6 and 28 Atomic mass of the metal would be1) 18.62) 283) 46.64) 56?
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