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White light is used to illuminate the two slits in Young's experiment. The separation between the slits is b and the screen is at a distance d (>> b) from the slits. At a point directly in front of one of the slits, certain wavelengths are missing. The missing wavelength(s) is/are
(1) λ = b²/d
(2) λ = b²/5d
(3) λ = b²/3d
(4) All of these?
(1) λ = b²/d
(2) λ = b²/5d
(3) λ = b²/3d
(4) All of these?
Most Upvoted Answer
White light is used to illuminate the two slits in Young's experiment....
Understanding Young's Experiment with White Light
In Young's double-slit experiment, white light is used to demonstrate the interference of light waves. When light passes through two closely spaced slits, it creates a pattern of bright and dark fringes on a screen.
Wavelengths and Interference
- The interference pattern depends on the wavelength of the light.
- At certain points on the screen, constructive interference occurs, resulting in bright spots, while at other points, destructive interference leads to dark spots.
Condition for Missing Wavelengths
- Directly in front of one slit, we observe certain wavelengths missing from the spectrum due to destructive interference.
- The condition for destructive interference is given by the formula:
d sin θ = (m + 0.5) λ, where m is the order of the minimum.
Calculating Missing Wavelengths
- For small angle approximations (d >> b), we have:
sin θ ≈ y/d, where y is the distance from the center to the minimum.
- The general form indicates that certain wavelengths will not be visible at specific points depending on the slit separation (b) and distance to the screen (d).
Identifying Missing Wavelengths
- The specific wavelengths missing can be derived as:
- λ = b²/d
- λ = b²/5d
- λ = b²/3d
Conclusion
- Therefore, the missing wavelengths are indeed:
- λ = b²/d
- λ = b²/5d
- λ = b²/3d
- This implies that options (1), (2), and (3) are all valid. Thus, the answer is:
- (4) All of these.
Understanding this concept is crucial for grasping the principles of wave interference and the behavior of light in various mediums.
In Young's double-slit experiment, white light is used to demonstrate the interference of light waves. When light passes through two closely spaced slits, it creates a pattern of bright and dark fringes on a screen.
Wavelengths and Interference
- The interference pattern depends on the wavelength of the light.
- At certain points on the screen, constructive interference occurs, resulting in bright spots, while at other points, destructive interference leads to dark spots.
Condition for Missing Wavelengths
- Directly in front of one slit, we observe certain wavelengths missing from the spectrum due to destructive interference.
- The condition for destructive interference is given by the formula:
d sin θ = (m + 0.5) λ, where m is the order of the minimum.
Calculating Missing Wavelengths
- For small angle approximations (d >> b), we have:
sin θ ≈ y/d, where y is the distance from the center to the minimum.
- The general form indicates that certain wavelengths will not be visible at specific points depending on the slit separation (b) and distance to the screen (d).
Identifying Missing Wavelengths
- The specific wavelengths missing can be derived as:
- λ = b²/d
- λ = b²/5d
- λ = b²/3d
Conclusion
- Therefore, the missing wavelengths are indeed:
- λ = b²/d
- λ = b²/5d
- λ = b²/3d
- This implies that options (1), (2), and (3) are all valid. Thus, the answer is:
- (4) All of these.
Understanding this concept is crucial for grasping the principles of wave interference and the behavior of light in various mediums.
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White light is used to illuminate the two slits in Young's experiment. The separation between the slits is b and the screen is at a distance d (>> b) from the slits. At a point directly in front of one of the slits, certain wavelengths are missing. The missing wavelength(s) is/are(1) λ = b²/d(2) λ = b²/5d(3) λ = b²/3d(4) All of these?
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White light is used to illuminate the two slits in Young's experiment. The separation between the slits is b and the screen is at a distance d (>> b) from the slits. At a point directly in front of one of the slits, certain wavelengths are missing. The missing wavelength(s) is/are(1) λ = b²/d(2) λ = b²/5d(3) λ = b²/3d(4) All of these? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about White light is used to illuminate the two slits in Young's experiment. The separation between the slits is b and the screen is at a distance d (>> b) from the slits. At a point directly in front of one of the slits, certain wavelengths are missing. The missing wavelength(s) is/are(1) λ = b²/d(2) λ = b²/5d(3) λ = b²/3d(4) All of these? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for White light is used to illuminate the two slits in Young's experiment. The separation between the slits is b and the screen is at a distance d (>> b) from the slits. At a point directly in front of one of the slits, certain wavelengths are missing. The missing wavelength(s) is/are(1) λ = b²/d(2) λ = b²/5d(3) λ = b²/3d(4) All of these?.
White light is used to illuminate the two slits in Young's experiment. The separation between the slits is b and the screen is at a distance d (>> b) from the slits. At a point directly in front of one of the slits, certain wavelengths are missing. The missing wavelength(s) is/are(1) λ = b²/d(2) λ = b²/5d(3) λ = b²/3d(4) All of these? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about White light is used to illuminate the two slits in Young's experiment. The separation between the slits is b and the screen is at a distance d (>> b) from the slits. At a point directly in front of one of the slits, certain wavelengths are missing. The missing wavelength(s) is/are(1) λ = b²/d(2) λ = b²/5d(3) λ = b²/3d(4) All of these? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for White light is used to illuminate the two slits in Young's experiment. The separation between the slits is b and the screen is at a distance d (>> b) from the slits. At a point directly in front of one of the slits, certain wavelengths are missing. The missing wavelength(s) is/are(1) λ = b²/d(2) λ = b²/5d(3) λ = b²/3d(4) All of these?.
Solutions for White light is used to illuminate the two slits in Young's experiment. The separation between the slits is b and the screen is at a distance d (>> b) from the slits. At a point directly in front of one of the slits, certain wavelengths are missing. The missing wavelength(s) is/are(1) λ = b²/d(2) λ = b²/5d(3) λ = b²/3d(4) All of these? in English & in Hindi are available as part of our courses for NEET.
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White light is used to illuminate the two slits in Young's experiment. The separation between the slits is b and the screen is at a distance d (>> b) from the slits. At a point directly in front of one of the slits, certain wavelengths are missing. The missing wavelength(s) is/are(1) λ = b²/d(2) λ = b²/5d(3) λ = b²/3d(4) All of these?, a detailed solution for White light is used to illuminate the two slits in Young's experiment. The separation between the slits is b and the screen is at a distance d (>> b) from the slits. At a point directly in front of one of the slits, certain wavelengths are missing. The missing wavelength(s) is/are(1) λ = b²/d(2) λ = b²/5d(3) λ = b²/3d(4) All of these? has been provided alongside types of White light is used to illuminate the two slits in Young's experiment. The separation between the slits is b and the screen is at a distance d (>> b) from the slits. At a point directly in front of one of the slits, certain wavelengths are missing. The missing wavelength(s) is/are(1) λ = b²/d(2) λ = b²/5d(3) λ = b²/3d(4) All of these? theory, EduRev gives you an
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