Which of the following is Hardy-Ramanujan Number ?a)1724b)1725c)1727 ...
This story is very famous among mathematicians. 1729 is sometimes called the “Hardy-Ramanujan number”.
There are two ways to say that 1729 is the sum of two cubes. 1x1x1=1; 12x12x12=1728. So 1+1728=1729 But also: 9x9x9=729; 10x10x10=1000. So 729+1000=1729 There are other numbers that can be shown to be the sum of two cubes in more than one way, but 1729 is the smallest of them.
Ramanujan did not actually discover this fact. It was known in 1657 by a Frenchmathematician Bernard Franicle de Bessy.
But it got famous after the ramanujans above conversation.
So it's famously known as Ramanujan Number.
Which of the following is Hardy-Ramanujan Number ?a)1724b)1725c)1727 ...
Explanation:
The Hardy-Ramanujan number, also known as the Taxicab number, is a number that can be expressed as the sum of two positive cubes in two different ways. It is named after the British mathematician G.H. Hardy and the Indian mathematician Srinivasa Ramanujan, who studied these numbers.
In order to determine which of the given numbers is a Hardy-Ramanujan number, we need to check if the number can be expressed as the sum of two positive cubes in two different ways.
Checking the options:
a) 1724:
To check if 1724 is a Hardy-Ramanujan number, we need to find two pairs of positive integers (a, b) and (c, d) such that a^3 + b^3 = c^3 + d^3 = 1724.
However, after trying different combinations, we cannot find such pairs. Therefore, 1724 is not a Hardy-Ramanujan number.
b) 1725:
Similar to the previous option, we need to find two pairs of positive integers (a, b) and (c, d) such that a^3 + b^3 = c^3 + d^3 = 1725.
Again, after trying different combinations, we cannot find such pairs. Therefore, 1725 is not a Hardy-Ramanujan number.
c) 1727:
Once again, we need to find two pairs of positive integers (a, b) and (c, d) such that a^3 + b^3 = c^3 + d^3 = 1727.
After trying different combinations, we cannot find such pairs. Therefore, 1727 is not a Hardy-Ramanujan number.
d) 1729:
To determine if 1729 is a Hardy-Ramanujan number, we need to find two pairs of positive integers (a, b) and (c, d) such that a^3 + b^3 = c^3 + d^3 = 1729.
Interestingly, we can find two pairs that satisfy this condition:
1^3 + 12^3 = 9^3 + 10^3 = 1729
Therefore, 1729 is a Hardy-Ramanujan number.
Conclusion:
Out of the given options, only 1729 is a Hardy-Ramanujan number. The other options (1724, 1725, and 1727) do not satisfy the condition of being expressible as the sum of two positive cubes in two different ways.