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500cm of oxygen was collected over water at 30°c and 752mmhg. what is the volume of dry oxygen at s.t.p(vapour pressure of water at 30°c is equal to 32mmhg?
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500cm of oxygen was collected over water at 30°c and 752mmhg. what is ...
Understanding the Problem
To calculate the volume of dry oxygen at standard temperature and pressure (STP), we need to account for the water vapor present in the collected gas.
Given Data
- Volume of gas collected (V) = 500 cm³
- Temperature (T) = 30°C
- Total pressure (P_total) = 752 mmHg
- Vapor pressure of water at 30°C (P_H2O) = 32 mmHg
Step 1: Calculate the Partial Pressure of Dry Oxygen
- The partial pressure of dry oxygen (P_O2) can be determined using the formula:
P_O2 = P_total - P_H2O
- Substituting the values:
P_O2 = 752 mmHg - 32 mmHg = 720 mmHg
Step 2: Convert the Partial Pressure to STP Conditions
At STP (0°C and 1 atm or 760 mmHg), we need to find the volume of dry oxygen. We will use the Ideal Gas Law principle.
Step 3: Use the Combined Gas Law
Using the formula:
(P1 * V1) / T1 = (P2 * V2) / T2
Where:
- P1 = 720 mmHg (pressure of dry oxygen)
- V1 = 500 cm³ (initial volume)
- T1 = 303 K (30°C + 273)
- P2 = 760 mmHg (pressure at STP)
- T2 = 273 K (0°C)
- V2 = ? (volume of dry oxygen at STP)
Step 4: Calculate V2
Rearranging the equation for V2:
V2 = (P1 * V1 * T2) / (P2 * T1)
Substituting the values:
V2 = (720 mmHg * 500 cm³ * 273 K) / (760 mmHg * 303 K)
Calculating gives approximately:
V2 ≈ 479.5 cm³
Final Result
The volume of dry oxygen at STP is approximately 479.5 cm³.
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500cm of oxygen was collected over water at 30°c and 752mmhg. what is the volume of dry oxygen at s.t.p(vapour pressure of water at 30°c is equal to 32mmhg?
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