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If(12+22+32+…..+102)=385,then the value of (22+42+62 + …+202) is :

  • a)
    770

  • b)
    1155

  • c)
    1540

  • d)
    (385*385)

Correct answer is option 'C'. Can you explain this answer?

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Answers

Sandhya Grewal
Jun 13, 2018
Related If(12+22+32+…..+102)=385,then the value of (22+42+62+ …+202) is :a)770b)1155c)1540d)(385*385)Correct answer is option 'C'. Can you explain this answer?
(1^2+2^2+3^2+....10^2)=385

(2^2+4^2+6^2+....+20^2)=2^2(1^2+2^2+ 3^2+....+10^2 )

 =4(385)

 =1540

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(1^2+2^2+3^2+....10^2)=385(2^2+4^2+6^2+....+20^2)=2^2(1^2+2^2+ 3^2+....+10^2 )=4(385)=1540